Alright remember, if any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
k+1=0
k-5=0
Set the first factor equal to 0 and solve
k=-1
Set the next factor equal to 0 and solve
k=5
The final solution is all the values that make (k+1)(k-5)=0 true.
k=-1, 5
Hope this helped you out :)
Answer:
11.5 tanks of gas
Step-by-step explanation:
23/2
11.5
Answer:
Austin and Devyn.
Step-by-step explanation:
1/3 and 2/6 are equal fractions.
Answer:
Option A
Step-by-step explanation:
Given:
- a. 3x-5= 3x + 5
- b. 3x-5= 3x - 5
- c. 3x - 5 = 2x+5
- d. 3x-5 = 2x + 10
To find:
- Which one of the linear equations have no solution.
Solution:
a) 3x-5= 3x + 5
Add 5 to both sides
3x-5= 3x + 5
3x - 5 + 5 = 3x + 5 + 5
Simplify
(Add the numbers)
3x - 5 + 5 = 3x + 5 + 5
3x = 3x + 5 + 5
(Add the numbers)
3x = 3x + 5 + 5
3x = 3x + 10
Subtract 3x from both sides
3x = 3x + 10
3x - 3x = 3x + 10 - 3
Simplify
(Combine like terms)
3x -3x = 3x + 10 - 3
0 = 3x + 10 - 3
(Combine like terms)
0 = 3x + 10 - 3
0 = 10
The input is a contradiction: it has no solutions
b) 3x-5= 3x - 5
Since both sides equal, there are infinitely many solutions.
c) 3x - 5 = 2x+5
Add 5 to both sides
3x = 2x + 5 + 5
Simplify 2x + 5 + 5 to 2x + 10
3x = 2x + 10
Subtract 2x from both sides
3x - 2x = 10
Simplify 3x - 2x to x.
x = 10
d) 3x-5 = 2x + 10
Add 5 to both sides
3x = 2x + 10 + 5
Simplify 2x + 10 + 5 to 2x + 15
3x = 2x + 15
Subtract 2x from both sides
3x - 2x = 15
Simplify 3x -2x to x.
x = 15
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Answer:
As you can see all c and d both have solutions, eliminating them as options. Option B has infinite solutions leaving Option A which has no solutions.
Therefore, <u><em>Option A</em></u> is the linear equation that has no solution.
Answer:
Last option?
Step-by-step explanation:
ax+by=c
4x+6y=60
a=4
b=6
c=60