32 models need to make model of 3200.
Given that a 1 model contain 100.
Two series of numbers, usually empirical data, that are proportional or proportional if their respective elements are in constant proportion, called the scaling factor or the rate constant.
One model has 100 elements.
Now, we have to find how many model contains 3200 elements.
So, 1 model=100 elements
n model =3200 elements
We will write this in proportion as
1/n=100/3200
Applying the cross multiply, we get
3200×1=n×100
Divide both sides with 100, we get
3200/100=100n/100
3200/100=n
32=n
Hence, the 32 models contain 3200 elements when one contain 100 elements.
Learn more about proportional from here brainly.com/question/23536327
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Answer:
What is the Question so I can answer?
Step-by-step explanation:
It’s C because through a Venn diagram C depicts both French and Spanish.
Let x = # of tickets sold in advance
Let y = # of tickets sold the day of
Cost of the tickets & total sales: 6x & 10y = 6828
You also know y = x + 206
Take the equation mentioned above y = x + 206 and sub it in anywhere the variable y is in the other equations so you'll have this:
6x + 10(x+206) = 6828
Now solve for x to get x = 298
To finish the problem, you must now find the number of y tickets sold.
Sub your x value that you found back into the equation y = x + 206 and you'll get y = 504.
So, 298 tickets were sold in advance and 504 tickets were sold the day of
Answer:
Step-by-step explanation:
idk
