<em>AC bisects ∠BAD, => ∠BAC=∠CAD ..... (1)</em>
<em>thus in ΔABC and ΔADC, ∠ABC=∠ADC (given), </em>
<em> ∠BAC=∠CAD [from (1)],</em>
<em>AC (opposite side side of ∠ABC) = AC (opposite side side of ∠ADC), the common side between ΔABC and ΔADC</em>
<em>Hence, by AAS axiom, ΔABC ≅ ΔADC,</em>
<em>Therefore, BC (opposite side side of ∠BAC) = DC (opposite side side of ∠CAD), since (1)</em>
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Hence, BC=DC proved.
Answer:
It took 2.5 (2 and a half) minutes to fill up one tire
Step-by-step explanation:
Hope this helps :)
Answer:
.
Step-by-step explanation:
Answer:
y = 7x + 12
Step-by-step explanation:
Slope (m) = 7
Line is passing through the point (0, 12)
y-intercept (b) = 12
Equation of line in slope-intercept form is given as:
