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sashaice [31]
3 years ago
9

Find the gradient of the line segment between the points (-3,2) and (-2,5).

Mathematics
2 answers:
gavmur [86]3 years ago
8 0

Answer:

\boxed{x=3}

Step-by-step explanation:

<h3>gradient = slope</h3>

Let's solve now

\red{( - 3 \:  \:  \:  \:  \:  \: 2)} =  >\green{ (x1 \:  \:  \:  \:  \: y1) }\\ \red{( - 2 \:  \:  \:  \:  \:  \: 5 ) }=  >\green{ (x2 \:  \:  \:  \:  \: y2)}\\

\blue{slope =  \frac{y1 - y2}{x1 - x2} } \\  =  \frac{2 - 5}{ - 3 - ( - 2)} \\  =  \frac{ - 3}{ - 3 + 2}  \\  =  \frac{ - 3}{ - 1} \\  = 3

Anna007 [38]3 years ago
6 0

Answer:

<h2>-3</h2>

Solution,

Let the points be A and B

A(-3,2)------->( X1,y1)

B(-2,5)------>( x2,y2)

Now,

gradient means slope.

slope =  \frac{y2 - y1}{x2 - x1}  \\  \:  \:  \:  \:  \:  \:  =  \frac{5 - 2}{ - 2 - ( - 3)}  \\  \:  \:  \:  \:  \:   =  \frac{ - 3}{ - 2 + 3}  \\  \:  \:  \:  \:  \:   = \frac{ - 3}{1}  \\  \:  \:  \:  =  - 3

Hope this helps..

Good luck on your assignment..

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1.25a+3&gt;0.5a-6 and 2.5a-1&gt;=9-1.5a
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The solution to the compound inequality given as: 1.25a+3>0.5a-6 and 2.5a-1>=9-1.5a is a > -12 and a>= 2.5

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