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puteri [66]
3 years ago
7

the ratio of the number of skiers who bought passes to the number of snowboaders who bought season passes is 1:2 . if 1250 more

snowboarders bought season passes then skiers , how many snowboarders and how many skiers bought season passes
Mathematics
1 answer:
viva [34]3 years ago
3 0
If a ratio of skiers and snumboarders is 1:2, and if there are 1250 snowboarders more than skiers, it means that is that there 2500 snowboarders and 1250 skiers.

How to check it? 2500 is 1250 more than 1250 and the ratio is still 1:2 (there are two times more snowboarders than skiers). Both conditions are fulfiled, so it's correct.
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Remote interior angles are formed on the outside of a triangle when a side is extended beyond the triangle true or false ?
sweet-ann [11.9K]
I believe it would be true.
However remote interior angles are formed on the outside of a triangle when a side is extended beyond the vertex, not triangle.
7 0
3 years ago
Elle has a sticker book with 12 pages of stickers. Her friend Erin's book has 3 times more pages. How many pages are in Erin's b
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Answer:

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Step-by-step explanation:

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5 0
3 years ago
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HELP
Bumek [7]

Answer:B.x = 2

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Step-by-step explanation:

7 0
3 years ago
Prove De Morgan's law by showing that each side is a subset of the other side by considering x ∈ A⎯⎯⎯ A ¯ ∩ B⎯⎯⎯ B ¯ .
adelina 88 [10]

Solution :

We have to prove that $\overline{A \cup B} = \overline{A} \cap \overline{B}$   (De-Morgan's law)

Let  $x \in \bar{A} \cap \bar{B}, $ then $x \in \bar{A}$ and $x \in \bar{B} $

and so $x \notin \bar{A}$ and $x \notin \bar{B} $.

Thus, $x \notin A \cup B$ and so $x \in \overline{A \cup B}$

Hence, $\bar{A} \cap \bar{B} \subset \overline{A \cup B}$   .........(1)

Now we will show that $\overline{A \cup B} \subset \overline{A} \cap \overline{B}$

Let $x \in \overline{A \cup B}$ ⇒ $x \notin A \cup B$

Thus x is present neither in the set A nor in the set B, so by definition of the union of the sets, by definition of the complement.

$x \in \overline{A}$ and  $x \in \overline{B}$

Therefore, $x \in \overline{A} \cap \overline{B}$ and we have $\overline{A \cup B} \subset \overline{A} \cap \overline{B}$  .............(2)

From (1) and (2),

$\overline{A \cup B} = \overline{A} \cap \overline{B}$

Hence proved.

3 0
3 years ago
 please help find out what is b/3+17=48
ale4655 [162]
-- Subtract 17 from each side --- b/3 = 31 --- Multiply each side by 3 --- b = 93 . Note that you don't 'move' things from one side to the other. You simply do the same thing to both sides.
7 0
4 years ago
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