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Elis [28]
2 years ago
5

The table shows the number of candies packed by Machine C. The equation shows the number of candies packed by Machine D. In both

representations, x is a measure of the number of minutes and y is a measure of the number of candies packed.
Machine C Candy Packing
x (minutes) y (candies)
2 150
4 300
6 450
8 600


Machine D: y = 130x

How many more candies could machine D pack than machine C in 11 minutes?
65
130
450
605
Mathematics
2 answers:
german2 years ago
5 0
<span>The correct answer is D) 605</span>
Step by step answer:
Divide 2 by 150 and you will get 75, meaning that Machine J packed 75 candies per minute. Machine K packed 130 candies per minute as it stated. In order to figure out how many more candies Machine J packed then Machine K in 11 minutes, you would need to figure out how many more candies it packed in one minute then multiply by 11. In this case Machine J packed 55 more then Machine K in one minute, therefore Machine J packed 605 more than Machine K in 11 minutes.
Hope this helped!
Rashid [163]2 years ago
4 0

Machine C makes 75 candies per minute.

Machine D makes 130 candies per minute.

Difference is 55


55 * 11 minutes = 605 candies.

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Square root of 1 is 1

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4 0
3 years ago
The population of a small town is decreasing exponentially at a rate of 14.3% each year. The current population is 9,400 people.
KonstantinChe [14]

Using an exponential function, the inequality is given as follows:

9400(0.857)^t < 6000

The solution is t > 2.9, hence the tax status will change within the next 3 years.

<h3>What is an exponential function?</h3>

A decaying exponential function is modeled by:

A(t) = A(0)(1 - r)^t

In which:

  • A(0) is the initial value.
  • r is the decay rate, as a decimal.

For this problem, the parameters are given as follows:

A(0) = 9400, r = 0.143.

The population after t years is modeled by:

A(t) = A(0)(1 - r)^t

A(t) = 9400(1 - 0.143)^t

A(t) = 9400(0.857)^t

The tax status will change when:

A(t) < 6000

Hence the inequality is:

9400(0.857)^t < 6000

Then:

(0.857)^t < \frac{6000}{9400}

\log{(0.857)^t} < \log{\left(\frac{6000}{9400}\right)}

t\log{0.857} < \log{\left(\frac{6000}{9400}\right)}

Since both logs are negative:

t > \frac{\log{\left(\frac{6000}{9400}\right)}}{\log{0.857}}

t > 2.9.

The solution is t > 2.9, hence the tax status will change within the next 3 years.

More can be learned about exponential functions at brainly.com/question/25537936

#SPJ1

7 0
1 year ago
Simplify: (1/2)^4 <br><br> please solve this problem
dsp73

Answer:

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Step-by-step explanation:

5 0
3 years ago
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