Question

What is true about the sum of the two polynomials ? 6s^2t-2st^2 and 4s^2t- 3st^2? The sum of a binomial is 2 . the sum of a binomial is 3 . the sum of a trinomial is 2 . the sum of a trinomial is 3.

Answer 1

The sum of the polynomials will be:
(6s^2t-2st^2)+(4s^2t-3st^2)
=(6s^2t+4s^2t)+(-2st^2-3st^2)
=10s^2t-5st^2
Thus the answer is:10s^2t-5st^2

Answer 2

Answer:

A. The sum of binomial is 2.

Step-by-step explanation:

We are given that two polynomials

$6s^2t-2st^2$

$4s^2t-3st^2$

We have to find the sum of the two polynomials

Let $p=6s^2t-2st^2$

$q=4s^2t-3st^2$

Adding two polynomials then we get

$p+q=6s^2t-2st^2+4s^2t-3st^2$

$p+q=6s^2t+4s^2t-2st^2-3st^2$

$p+q=(6+4)s^2t-(2+3)st^2$

By taking common $s^2t$ from  $6s^2t\;and\; 4s^2t$

and $st^2$ from $2st^2$ and$3st^2$

Therefore, we have sum two polynomials

$p+q=10s^2t-5st^2$

Binomial means the polynomial contains two terms

Therefore, the sum of binomial is '2'.

Hence , option A is true.

A. The sum of binomial is 2.