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Jlenok [28]
3 years ago
10

Can someone please help me?

Mathematics
1 answer:
lara31 [8.8K]3 years ago
3 0

Answer:

I think 6 but Idk

Step-by-step explanation:

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In a circle with a radius of 3 ft, an arc is intercepted by a central angle of 2π3 radians. What is the length of the arc?
madreJ [45]
The correct question is 
<span>In a circle with a radius of 3 ft, an arc is intercepted by a central angle of 2π/3 radians. What is the length of the arc? 

we know that
in a circle
</span>2π radians -----------------> lenght of (2*π*r)
2π/3 radians--------------> X
X=[(2π/3)*(2π*r)]/[2π]=(2π/3)*r

 the lenght  of the arc=(2π/3)*3=2π ft

the answer is 2π ft




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CAN SOMEONE JUST PLEASE ANSWER THIS ASAP FOR BRAINLIEST!!!!
grigory [225]

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Step-by-step explanation:

Vertex is what is being asked by the question, and those points are given in the question. Vertex form is a(x-p)^2 + q, where 5 is the x of the vertex, and 25 is the y of the vertex

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Set up an algebraic equation and then solve.
svetlana [45]

Answer:

Width: 6

Length: 20

Step-by-step explanation:

So the area of a rectangle can be defined as: A=wl where w=width and l=length.

In this case we don't know what the length is, so let's just say the length is the variable l, and since the width is 14 units less than the length, we can express it as (l-14). this gives us the equation: A=l(l-14)=l^2-14l. We can solve for l, since we're given the area which is 120. So let's set the equation equal to that:

Original Equation:

A=l^2-14l

Substitute 120 as A (given)

120=l^2-14l

There is many ways to solve this equation: factoring, quadratic equation, completing the square etc... but in this case I'll just complete the square

Add (b/2)^2 to both sides to complete the square

120+(\frac{-14}{2})^2=l^2-14l+(\frac{-14}{2})^2

Simplify

169=l^2-14l+49

Rewrite right side a square binomial

169=(l-7)^2

Take the square root of both sides

13=l-7\\

Add 7 to both sides

20=l

to solve for width simply subtract 14 from the length which is 20, so the width is 6

Width: 6

L: 20

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