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3 years ago

13

The table shows five transactions and the resulting account balance in a bank account, except some numbers are missing. Fill the

missing numbers

1 answer:

Allushta [10]3 years ago

5 0

Transaction 3= -155.15
Transaction 4= -223.75

You might be interested in

Is 45 greater than 451/2

slava [35]

Answer:

No, it is not

Step-by-step explanation:

In order to compare the two numbers, start by simplifying 451/2

451 ÷ 2 = 225 R1

452/2 = 225 1/2

225 1/2 _ 45

225 1/2 > 45

5 0

3 years ago

Read 2 more answers

Three solutions for 5x+7y=19

ddd [48]

Just sub in ANY number for x and solve for y

5x + 7y = 19.....lets say x = 0
5(0) + 7y = 19
7y = 19
y = 19/7...so when x = 0, y = 19/7.....(0,19/7)

5x + 7y = 19....lets say x = 1
5(1) + 7y = 19
5 + 7y = 19
7y = 19 - 5
7y = 14
y = 14/7
y = 2.....so when x = 1, y = 2......(1,2)

5x + 7y = 19.....lets say x = 3
5(3) + 7y = 19
15 + 7y = 19
7y = 19 - 15
7y = 4
y = 4/7...so when x = 3, y = 4/7.....(3,4/7)

7 0

3 years ago

Write the number name and expanded form for 710,231

vekshin1

Answer:

seven hundred ten and two hundred and thirty one 700,000+ 10,000+ 200+30+1

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Please help i will mark brainliest

Evgen [1.6K]

Answer:

2. $\left[\begin{array}{ccc}1&4\\0&3\\\end{array}\right]$

3. $\left[\begin{array}{ccc}-3&21&60\\-15&9&-45\\\end{array}\right]$

4. $\left[\begin{array}{ccc}6&-14\\-2&-6\\\end{array}\right]$

Step-by-step explanation:

2. This matrix is easy, as it just requires addition.

$\left[\begin{array}{ccc}1&4\\0&3\\\end{array}\right]$ + $\left[\begin{array}{ccc}0&0\\0&0\\\end{array}\right]$ = $\left[\begin{array}{ccc}1&4\\0&3\\\end{array}\right]$

3. This matrix requires for the matrices to be multiplied first, then added.

$\left[\begin{array}{ccc}9&-15&18\\-27&15&-9\\\end{array}\right]$ + $\left[\begin{array}{ccc}-12&36&42 \\12& -6 & -36 \\\end{array}\right]$ = $\left[\begin{array}{ccc}-3&21&60\\-15&9&-45\\\end{array}\right]$

4. Here we can add the last 2 matrices to find x.

$\left[\begin{array}{ccc}2&-8\\-4&2\\\end{array}\right]$ + $\left[\begin{array}{ccc}4&-6\\2&-8 \\\end{array}\right]$ = $\left[\begin{array}{ccc}6&-14\\-2&-6\\\end{array}\right]$

Hope this helps! (Please consider giving brainliest)

4 0

3 years ago

Can someone please help

Neporo4naja [7]

All I know is 5 and 6.

5. -7 (the picture is the model to draw)
6. -5

8 0

3 years ago