Answer:
B
Step-by-step explanation:
Using the determinant to determine the type of zeros
Given
f(x) = ax² + bx + c ( a ≠ 0 ) ← in standard form, then the discriminant is
Δ = b² - 4ac
• If b² - 4ac > 0 then 2 real and distinct zeros
• If b² - 4ac = 0 then 2 real and equal zeros
• If b² - 4ac < 0 then 2 complex zeros
Given
f(x) = (x - 1)² + 1 ← expand factor and simplify
= x² - 2x + 1 + 1
= x² - 2x + 2 ← in standard form
with a = 1, b = - 2, c = 2, then
b² - 4ac = (- 2)² - (4 × 1 × 2) = 4 - 8 = - 4
Since b² - 4ac < 0 then the zeros are complex
Thus P(x) has no real zeros
Answer:
the second one
Step-by-step explanation:
Answer:
i think its 360.......
Step-by-step explanation:
i hope it helps
Hello,
f(x)=2x²+1
f(ax+b)=2(ax+b)²+1=2(a²x²+2abx+b²)+1=2a²x²+4abx+2b²+1
af(x)+b=a(2x²+1)+b=2ax²+a+b
And f(ax+b)≠af(x)+b not linear
Answer:
40,885,048
Step-by-step explanation:
first find 3^12 and then find 7^9.
3^12 = 531,441
7^9 = 40,353,607
Add these together and you'll get 40,885,048.
Welcome! Hope this helps.
