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Kamila [148]
3 years ago
12

Line AB is parallel to line CD, what is the measure of angle CFE

Mathematics
1 answer:
Novay_Z [31]3 years ago
3 0

Answer:

.

Step-by-step explanation:

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X/-9 =3<br>I dont understand this.​
STatiana [176]

Final Answer: x = -27

Steps/Equations:

Question: \frac{x}{-9} = 3

Step 1: Move the negative sign to the left side.

-\frac{x}{9} = 3

Step 2: Multiply both sides by 3.

-x = 3 * 9

Step 3: Simplify 3 * 9 to 27.

-x = 27

Step 4: Multiply both sides by -1.

x = -27

~I hope I helped :)~

5 0
3 years ago
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What is the slope of the line with points of (0,-1)) and (2,3)
ycow [4]

Answer:

2

Step-by-step explanation:4divided by 2 =2

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3 years ago
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Round 14.857 to the nearest tenth. A. 15.0 B. 14.8 C. 14.9 D. 10.0
LenKa [72]
C. 14.9  because the second number is 5 so you drop the seven and the 5 and round the 8 up to 9
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3 years ago
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In physics, if a moving object has a starting position at so, an initial velocity of vo, and a constant acceleration a, the
emmasim [6.3K]

Answer:

a=\frac{2S -2v_ot-2s_o}{t^2}

Step-by-step explanation:

We have the equation of the position of the object

S = \frac{1}{2}at ^2 + v_ot+s_o

We need to solve the equation for the variable a

S = \frac{1}{2}at ^2 + v_ot+s_o

Subtract s_0 and v_0t on both sides of the equality

S -v_ot-s_o = \frac{1}{2}at ^2 + v_ot+s_o - v_ot- s_o

S -v_ot-s_o = \frac{1}{2}at ^2

multiply by 2 on both sides of equality

2S -2v_ot-2s_o = 2*\frac{1}{2}at ^2

2S -2v_ot-2s_o =at ^2

Divide between t ^ 2 on both sides of the equation

\frac{2S -2v_ot-2s_o}{t^2} =a\frac{t^2}{t^2}

Finally

a=\frac{2S -2v_ot-2s_o}{t^2}

5 0
3 years ago
Which shows one way to determine the factors of 4x3 + x2 – 8x – 2 by grouping?
lara31 [8.8K]
Group first 2 and group last 2 and find factors and undistribute

(4x^3+x^2)+(-8x-2)
(x^2)(4x+1)+(-2)(4x+1)
x^2(4x+1)-2(4x+1)
answer is first one

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3 years ago
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