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Andre45 [30]
3 years ago
7

Can anyone help me with THIS and the other TWO‼️PLEASE I’m really need HELP

Mathematics
1 answer:
scZoUnD [109]3 years ago
4 0

Answer:

y = 3x +2

Step-by-step explanation:

It is helpful to be acquainted with the parts of at least a couple of different forms of the equation for a line.

You are given the equation of a line in "slope-intercept" form. It looks like ...

... y = mx + b . . . . . . . where m=-1/3 and b=-1

The coefficient of x, which is m, is the slope of the line. That is -1/3 for the given line.

The relationship between the slopes of perpendicular lines is that they multiply to give -1. We say each is the opposite reciprocal of the other. If we let "m" stand for the slope of the perpendicular line, it satisfies the equation ...

...(m)(-1/3) = -1

... m = -1/(-1/3) = 3 . . . . . the slope of the perpendicular line is 3.

____

Here's where another form of the equation for a line is useful. We can write the "point-slope" form* as ...

... y = m(x -h) +k . . . . . . for a line of slope m through point (h, k)

We want our line of slope = 3 to go through the point (1, 5), so its equation can be ...

... y = 3(x -1) +5 . . . . . . . variation of "point-slope" form

The given equation is in slope-intercept form, and the question asks for "the" equation of the line, so we probably should write our answer in the same form as the given equation. We can do this by eliminating the parentheses and simplifying the equation we have.

... y = 3x -3 +5 . . . . eliminate parentheses using the distributive property

... y = 3x +2 . . . . . . collect terms

The graph shows our result is at least plausible: it looks like it is perpendicular, and it goes through the given point.

___

<em>*Comment on point-slope form</em>

Usually, you will see "point-slope" form written as ...

... y -k = m(x -h) . . . . . . . . standard version of "point-slope" form

When our intent is to use this form to get to slope-intercept form, it is more convenient to add k to this equation to get ...

... y = m(x -h) +k . . . . . . . occasionally useful version

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The answer would be graph B. 
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3 years ago
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2) In 1000 sq. meter of land a farmer cultivated 765 kg of rice with the wastage of 23.5%. I) Find the weight of the wastage. II
LiRa [457]

Answer:

Weight of wastage=179.775kg

weight of rice cultivated= 585.225 kg

percentage of rice cultivated=76.5%

Step-by-step explanation:

Area of land=100 square meters

Cultivated rice=765kg

Wastage=23.5%

1) Weight of the wastage=23.5% of 765kg

=23.5/100 × 765

=17977.5 / 100

=179.775 kg

2) Weight and percentage of rice cultivated.

weight of rice cultivated = 765 kg - 179. 775 kg

= 585.225 kg

percentage of rice cultivated = 100 - 23.5

= 76.5%

3) if area is increased 40 times in size

New area=1000 square meters × 40

=40,000 square meters

Cultivated rice= 765kg × 40

=30,600 kg

Cultivated rice excluding wastage=585.225 kg × 40

=23,409 kg

8 0
3 years ago
What is the probability of a customer buying a vegetable that is not an onion at this store?
alisha [4.7K]
Answer: 79%

That’s because it’s the middle probability it can’t be others because they are too high it too low
8 0
2 years ago
Subtract -13xy from -5xy so<br> -5xy -(-13xy)=?
S_A_V [24]

Answer:

8xy

Step-by-step explanation:

Subtract -13xy from -5xy

-5xy - (-13xy) =

-5xy + 13xy =

8xy

<em>good luck, i hope this helps:)</em>

3 0
3 years ago
Read 2 more answers
How do you solve these equations? I don't want you to answer all of them, just tell me how to solve each type of equation on the
miss Akunina [59]

Answer:

8. Identify the common denominator; express each fraction using that denominator; combine the numerators of those rewritten fractions and express the result over the common denominator. Factor out any common factors from numerator and denominator in your result. (It's exactly the same set of instructions that apply for completely numerical fractions.)

9. As with numerical fractions, multiply the numerator by the inverse of the denominator; cancel common factors from numerator and denominator.

10. The method often recommended is to multiply the equation by a common denominator to eliminate the fractions. Then solve in the usual way. Check all answers. If one of the answers makes your multiplier (common denominator) be zero, it is extraneous. (10a cannot have extraneous solutions; 10b might)

Step-by-step explanation:

For a couple of these, it is helpful to remember that (a-b) = -(b-a).

<h3>8d.</h3>

\dfrac{5}{x+2}+\dfrac{25-x}{x^2-3x-10}=\dfrac{5(x-5)}{(x+2)(x-5)}+\dfrac{25-x}{(x+2)(x-5)}\\\\=\dfrac{5x-25+25-x}{(x+2)(x-5)}=\dfrac{4x}{x^2-3x-10}

___

<h3>9b.</h3>

\displaystyle\frac{\left(\frac{x}{x-2}\right)}{\left(\frac{2x}{2-x}\right)}=\frac{x}{x-2}\cdot\frac{-(x-2)}{2x}=\frac{-x(x-2)}{2x(x-2)}=-\frac{1}{2}

___

<h3>10b.</h3>

\dfrac{3}{x-1}+\dfrac{6}{x^2-3x+2}=2\\\\\dfrac{3(x-2)}{(x-1)(x-2)}+\dfrac{6}{(x-1)(x-2)}=\dfrac{2(x-1)(x-2)}{(x-1)(x-2)}\\\\3x-6+6=2(x^2-3x+2) \qquad\text{multiply by the denominator}\\\\2x^2-9x+4=0 \qquad\text{subtract 3x}\\\\(2x-1)(x-4)=0 \qquad\text{factor; x=1/2, x=4}

Neither solution makes any denominator be zero, so both are good solutions.

8 0
3 years ago
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