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3 years ago

Which figures are polygons

Mathematics

1 answer:

Tatiana [17]3 years ago

5 0

The answer is A. A, D the reason being, is because polygons have sides C, and B have no sides so we can eliminate those immediately.

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Quadrilateral GHIJ is similar to quadrilateral KLMN. Find the measure of side NK.

Leokris [45]

Answer:
NK = 14.4

Step-by-step explanation:

Given the following question:

We know that the two sides are similar
JI = 3, NM = 7.2

<u>The scale factor is 2.4 since....</u>

$3\times2.4=7.2$

Knowing the two sides are similar and if we multiply JI by 2.4, we get NM we can easily do the same for JG and NK.

JG = 6
$6\times2.4=14.4$
$=14.4$

NK = 14.4

Hope this helps.

6 0

2 years ago

Read 2 more answers

In What quadrant is the point (-5, -5) located

sineoko [7]

Answer:

Since both values are negative, it can be found in the 3rd quadrant

<em>Feel free to mark this as brainliest :D</em>

4 0

3 years ago

Use the Polynomial Identity below to help you create a list of 10 Pythagorean Triples:

Stolb23 [73]

Answer:

(3,4,5)

(6,8,10)

(5,12,13)

(8,15,17)

(12,16,20)

(7,24,25)

(10,24,26)

(20,21,29)

(16,30,34)

(9,40,41)

Just choose 2 numbers from {1,2,3,4,5,6,7,8,...} and make sure the one you input for x is larger.

Post the three in the comments and I will check them for you.

Step-by-step explanation:

We need to choose 2 positive integers for x and y where x>y.

Positive integers are {1,2,3,4,5,6,7,.....}.

I'm going to start with (x,y)=(2,1).

x=2 and y=1.

$(2^2+1^2)^2=(2^2-1^2)^2+(2\cdot2\cdot1)^2$

$(4+1)^2=(4-1)^2+(4)^2$

$(5)^2=(3)^2+(4)^2$

So one Pythagorean Triple is (3,4,5).

I'm going to choose (x,y)=(3,1).

x=3 and y=1.

$(3^2+1^2)^2=(3^2-1^2)^2+(2\cdot3\cdot1)^2$

$(9+1)^2=(9-1)^2+(6)^2$

$(10)^2=(8)^2+(6)^2$

So another Pythagorean Triple is (6,8,10).

I'm going to choose (x,y)=(3,2).

x=3 and y=2.

$(3^2+2^2)^2=(3^2-2^2)^2+(2\cdot3\cdot2)^2$

$(9+4)^2=(9-4)^2+(12)^2$

$(13)^2=(5)^2+(12)^2$

So another is (5,12,13).

I'm going to choose (x,y)=(4,1).

$(4^2+1^2)^2=(4^2-1^2)^2+(2\cdot4\cdot1)^2$

$(16+1)^2=(16-1)^2+(8)^2$

$(17)^2=(15)^2+(8)^2$

Another is (8,15,17).

I'm going to choose (x,y)=(4,2).

$(4^2+2^2)^2=(4^2-2^2)^2+(2\cdot4\cdot2)^2$

$(16+4)^2=(16-4)^2+(16)^2$

$(20)^2=(12)^2+(16)^2$

We have another which is (12,16,20).

I'm going to choose (x,y)=(4,3).

$(4^2+3^2)^2=(4^2-3^2)^2+(2\cdot4\cdot3)^2$

$(16+9)^2=(16-9)^2+(24)^2$

$(25)^2=(7)^2+(24)^2$

We have another is (7,24,25).

You are just choosing numbers from the positive integer set {1,2,3,4,... } and making sure the number you plug in for x is higher than the number for y.

I will do one more.

Let's choose (x,y)=(5,1).

$(5^2+1^2)^2=(5^2-1^2)^2+(2\cdot5\cdot1)^2$

$(25+1)^2=(25-1)^2+(10)^2$

$(26)^2=(24)^2+(10)^2$

So (10,24,26) is another.

Let (x,y)=(5,2).

$(5^2+2^2)^2=(5^2-2^2)^2+(2\cdot5\cdot2)^2$

$(25+4)^2=(25-4)^2+(20)^2$

$(29)^2=(21)^2+(20)^2$

So another Pythagorean Triple is (20,21,29).

Choose (x,y)=(5,3).

$(5^2+3^2)^2=(5^2-3^2)^2+(2\cdot5\cdot3)^2$

$(25+9)^2=(25-9)^2+(30)^2$

$(34)^2=(16)^2+(30)^2$

Another Pythagorean Triple is (16,30,34).

Let (x,y)=(5,4)

$(5^2+4^2)^2=(5^2-4^2)^2+(2\cdot5\cdot4)^2$

$(25+16)^2=(25-16)^2+(40)^2$

$(41)^2=(9)^2+(40)^2$

Another is (9,40,41).

5 0

3 years ago

Graph B

lara [203]

Answer/Step-by-step explanation:

Slope (m) = rise/run

y-intercept (b) = starting value or the point on the y-axis where the line cuts across

✔️Slope (m) of skater 1:

Rise = 45

Run = 7.5

Slope (m) = 45/7.5 = 6

✔️ y-intercept (b) of Skater 1:

b = 0 (the y-axis is intercepted at 0)

✔️Skater 1 linear function in slope-intercept form, y = mx + b

Substitute m = 6 and b = 0 into y = mx + b

Linear function: y = 6x + 0

y = 6x

✔️Slope (m) of skater 2:

Rise = 30

Run = 15

Slope (m) = 30/15 = 2

✔️ y-intercept (b) of Skater 2:

b = 0 (the y-axis is intercepted at 0)

✔️Skater 2 linear function in slope-intercept form, y = mx + b

Substitute m = 2 and b = 0 into y = mx + b

Linear function: y = 2x + 0

y = 2x

7 0

3 years ago

The following numerically ordered sequence of numbers has a mean

Vladimir79 [104]

Median = middle number

Total ten numbers so
median =   (17 + b)/2
given median = 18
so
(17 + b)/ 2 = 18
17+b = 36
b = 36 - 17
b = 19

Now you have the data set
7, a , 12, 15 , 17, 19, 20, 22, 24 , 25

Mean =  (7 + a + 12+ 15 +17 + 19 + 20 + 22 +24  +25)/ 10
Given mean = 17

so
17 = (7 + a + 12+ 15 +17 + 19 + 20 + 22 +24  +25)/ 10
17 = (a + 161) / 10
a + 161 = 170
a = 170 - 161
a = 9

answer
a = 9
b = 19

7 0

3 years ago

Read 2 more answers