The function which represents the taxi fare in terms of distance d in meter is f(d) = 3.50 ×
+ 40 .
According to the question,
For first 500 meters cost is 40.00 and For each additional 300 meters cost is 3.50 .
Let, the total distance of taxi ride = d meters
Now, representing the equation of taxi fare in terms of distance when distance is less than 500
taxi fare = 3.50 × + 40
∴ f(d) = 3.50 × + 40
To know more about functions refer below link: brainly.com/question/12431044
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Answer:
Step-by-step explanation:
Answer:
t ≤ -7
Step-by-step explanation:
−4t≥28
−4/4 * t ≥ 28/4
−1 * t ≥ 7
-t ≥ 7
t ≤ -7
Answer: -3x + 8 should be your answer! A good way to get quick answers for questions like these would be https://www.cymath.com/answer.php which I just used to answer this question, hope it helps!
Looking at this problem in terms of geometry makes it easier than trying to think of it algebraically.
If you want the largest possible x+y, it's equivalent to finding a rectangle with width x and length y that has the largest perimeter.
If you want the smallest possible x+y, it's equivalent to finding the rectangle with the smallest perimeter.
However, the area x*y must be constant and = 100.
We know that a square has the smallest perimeter to area ratio. This means that the smallest perimeter rectangle with area 100 is a square with side length 10. For this square, x+y = 20.
We also know that the further the rectangle stretches, the larger its perimeter to area ratio becomes. This means that a rectangle with side lengths 100 and 1 with an area of 100 has the largest perimeter. For this rectangle, x+y = 101.
So, the difference between the max and min values of x+y = 101 - 20 = 81.
