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Ratling [72]
4 years ago
10

PLS HURRY THANK YOU.

Mathematics
1 answer:
SashulF [63]4 years ago
7 0

<u>Given</u>:

The arithmetic sequence is represented in the table.

The general form of the arithmetic sequence is given by

a_n=a_1+(n-1)d

We need to determine the value of the missing term.

<u>First term:</u>

From the table, we need to determine the first term of the arithmetic sequence.

From the table, the value of the first term is 3.

Thus, a_1=3

Hence, the first term is 3.

<u>Common difference:</u>

From the table, we can determine the common difference of the arithmetic sequence.

Thus, we have;

12 - 3 = 9

Hence, the common difference is d=9

<u>Value of the missing term:</u>

The value of the term 45 can be determined by substituting n = 45 in the general form a_n=a_1+(n-1)d

Thus, we have;

a_{45}=3+(45-1)(9)

a_{45}=3+(44)(9)

a_{45}=3+396

a_{45}=399

Hence, the value of the term 45 is 399.

Thus, the value of the missing term is 399.

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2 years ago
The officer stepped off 20 paces from E to G. If his pace is 2 1/2 feet long. How wide was the river?
Sergeeva-Olga [200]

Answer:

The wide of river is 50\ ft

Step-by-step explanation:

In this problem we know that

Triangles DEG and DEF are congruent by ASA (Angle-Side-Angle) Congruence

therefore

EG=EF

EG=20*(2\frac{1}{2})=20*\frac{5}{2}=50\ ft

8 0
4 years ago
Round to ten thousands 25497 54088
Inessa [10]
I think it's 254974090
4 0
3 years ago
NEED HELP ASAP!!! What is the interquartile range of the data set? Enter the answer in the box. Key: 1|5 means 15 A stem-and-lea
monitta
To find the interquartile range, you will list the data that is presented in the stem and leaf plot.

Find the median of the data (30.5)

Find the median of the lower half and the median of the upper half.

Subtract these two values.

The data are <u>20</u>, 25, 30, 30, 31, 40, 41, <u>49</u>.
                            27.5                40.5
40.5-27.5 = 13

The interquartile range is 13.
3 0
3 years ago
Read 2 more answers
Use the box plots comparing the number of male puppies and number of female puppies attending doggy daycare each day for a month
dalvyx [7]
  1. The IQR for the males' data is 25.
  2. The difference between the median of the males' data and the female's data is 14.
  3. The distribution of the males' data is skewed to the right and the median would be a better measure of the center. The distribution of the female's data is normal and the mean would be a better measure of the center.
  4. A reason for the outlier is that the number of dogs needing care increased.

<h3>What is the interquartile range?</h3>

The interquartile range for the males data is the difference between the third quartile and the first quartile.

IQR = third quartile - first quartile

25 - 0 = 25

Median = 20 - 6 = 14

An outlier is a number that is way smaller or way larger than that of other numbers in a data set.

To learn more about outliers, please check: brainly.com/question/27197311

#SPJ1

7 0
2 years ago
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