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Ede4ka [16]
2 years ago
12

a solid consists of cylinder surmounted by a right circular cone. The height of the cone is 2h. If the volume of the solid is 3

times the volume of the cone then what is the height of the cylinder. Plsss help fast
Mathematics
1 answer:
Mademuasel [1]2 years ago
8 0

Answer:

height of cylinder = 4/3 h

Step-by-step explanation:

The solid has a cylinder surmounted with a cone .Therefore, the volume of the solid is the sum of the cone and the cylinder.

volume of the solid = volume of cylinder + volume of cone

volume of the solid = πr²h + 1/3πr²h

let

height of the cylinder = H

recall

the height of the cone = 2h

volume of the solid = πr²h + 1/3πr²h

3(1/3πr²2h) = πr²H + 1/3πr²2h

2πr²h = πr²H + 2/3 πr²h

πr²(2h) = πr²(H + 2/3 h)

divide both sides by πr²

2h = H + 2/3 h

2h - 2/3h = H

H = 6h - 2h/3

H = 4/3 h

height of cylinder = 4/3 h

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Question 2
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The domain of the function is x ≤ 6.88

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<h3>Domain and Range</h3>
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Given the function of x expressed as:

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Answer: Box3 has 120 oranges.

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Box  has 130 oranges.

Step-by-step explanation:

I will answer this in English.

The question says:

3 boxes have 400 oranges.

The first one has 20 more than the second and 30 more than the third.

So we have 3 equations:

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