Arcsin x + arcsin 2x = π/3
arcsin 2x = π/3 - arcsin x
sin[arcsin 2x] = sin[π/3 - arcsin x] (remember the left side is like sin(a-b)
2x = sinπ/3 cos(arcsin x)-cosπ/3 sin(arc sinx)
2x = √3/2 . cos(arcsin x) - (1/2)x)
but cos(arcsin x) = √(1-x²)===>2x = √3/2 .√(1-x²) - (1/2)x)
Reduce to same denominator:
(4x) = √3 .√(1-x²) - (x)===>5x = √3 .√(1-x²)
Square both sides==> 25x²=3(1-x²)
28 x² = 3 & x² = 3/28 & x =√(3/28)
Answer:
53
Step-by-step explanation:
Answer:
The intersection point of the given lines is (1,1).
Step-by-step explanation:
Here, the given equations are:
y = - 2 x + 3
y = x
Substitute y = x in the first equation,
y = -2 x + 3 becomes y = -2 (y) + 3
or, y + 2 y = 3
or, 3 y = 3 ⇒ y = 3/3 = 1
⇒ y = 1
Now, as x = y ⇒ x = 1
Hence, the intersection points of the given lines is (1,1).
Answer:
-4 in
Step-by-step explanation:
4 inches underground, assuming that ground level is 0, is negative four inches.
