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Nina [5.8K]
2 years ago
12

Three tables are placed side by side. One table is 6 feet 3 inches wide, another is 3 feet 7 inches wide, and the third is 6 fee

t 6 inches wide. How wide are they combined?Write your answer in feet and inches. Use a number less than for 12 inches.
Mathematics
1 answer:
nevsk [136]2 years ago
7 0

Answer:

Total width of tables combined = 16 feet and 4 inches

Step-by-step explanation:

Given:

Width of tables

1) 6 feet 3 inches

2) 3 feet 7 inches

3) 6 feet 6 inches

The tables are combined. We need to find the total width.

Total width of the tables combined = Sum of the widths of the tables

⇒ 6\ ft\ 3\ in+3\ ft\ 7\ in + 6\ ft\ 6\ in

Adding feet and inches together.

⇒ (6+3+6)\ ft +(3+7+6)\ in

⇒ 15\ ft + 16\ in

[∵ 12\ in = 1\ ft , we can split 16\ in = 12\ in + 4\ in

⇒ 15\ ft + 12\ in+4\ in

⇒ 15\ ft + 1\ ft+4\ in

⇒ 16\ ft\ and\ 4\ in

Total width of tables combined = 16 feet and 4 inches

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Please help me do this problem! ‼️
blagie [28]
0 - 18 = -18

-18 + 9 = -9 ft
7 0
3 years ago
C = 200 – 7x + 0.345x2
fenix001 [56]

The way to find the domain and the range is illustrated below.

<h3>How to illustrate the information?</h3>

From the information, c(x) = 200 - 7x + 0.345x². It should be noted that the domain is the set of x-values that are feasible.

The range is the set of possible results for c(x). They are the possible costs. You can derive this from the fact that c(x) is a parabola and you can draw it, for which you can find the vertex of the parabola, the roots, the y-intercept, the shape.

You can substitute some values for x to help you, for example:

x      y

0    200

1    200 -7 +0.345 = 193.345

2    200 - 14 + .345 (4) = 187.38

3    200 - 21 + .345(9) = 182.105

4    200 - 28 + .345(16) = 177.52

5    200 - 35 + 0.345(25) = 173.625

6    200 - 42 + 0.345(36) = 170.42

10  200 - 70 + 0.345(100) =164.5

11 200 - 77 + 0.345(121) = 164.745

If the functions do not have real roots, then the costs never decrease to 0. The function starts at c(x) = 200, decreases until the vertex, (x =10, c=164.5) and starts to increase.

Then the range goes from 164.5 to infinity, limited to the solution for x = positive integers.

Learn more about domain on:

brainly.com/question/2264373

#SPJ1

Complete question:

the daily production cost, c, for x units is modeled by the equation: c = 200 – 7x 0.345x² explains how to find the domain and range of c.

4 0
1 year ago
(1+(0.065÷365))^365t=4
marta [7]
This is the future value quadrupled in t years at an annual interest rate of 6.5% compounded daily.  We need to find t.

1*(1+0.065/365)^(365t)t=4
take log on both sides,
365t(log(1+0.065/365)=log(4)
=>
365t=log(4)/log(1+0.065/365)
t=(log(4)/log(1+0.065/365))/365
=(1.38629/.000178066)/365
=21.33 years

Check with the rule of 69, applicable to continuous compounding (an approximation to current problem) to double money, it take 69/interest rate in % years.
=69/6.5
=10.62 years
To double twice (quadruple), it takes twice 10.62
=21.24 years, not that far from 21.33 that we got earlier.
7 0
3 years ago
A jar contains 8 white marbles, 6 black marbles, and 1 red marbles. If one marble is drawn at random, find the probability that
Mariana [72]

Answer:

Hi there!

6/15 is the probability that the marble is black!

Step-by-step explanation:

Oki, so lets's find the total number of marbles first!

8 + 6 + 1 = 14 + 1 = 15

And just turn it into a fraction!(very simple and easy)

6/15

5 0
3 years ago
Read 2 more answers
Tough one!
frosja888 [35]
Imx->0 (asin2x + b log(cosx))/x4 = 1/2 [0/0 form] ,applying L'Hospital rule ,we get

= > limx->0 (2a*sinx*cosx - (b /cosx)*sinx)/ 4x3 = 1/2 => limx->0 (a*sin2x - b*tanx)/ 4x3 = 1/2 [0/0 form],

applying L'Hospital rule again ,we get,

 = > limx->0 (2a*cos2x - b*sec2x) / 12x2 = 1/2

For above limit to exist,Numerator must be zero so that we get [0/0 form] & we can further proceed.

Hence 2a - b =0 => 2a = b ------(A)

limx->0 (b*cos2x - b*sec2x) / 12x2 = 1/2 [0/0 form], applying L'Hospital rule again ,we get,

= > limx->0 b*(-2sin2x - 2secx*secx.tanx) / 24x = 1/2 => limx->0 2b*[-sin2x - (1+tan2x)tanx] / 24x = 1/2

[0/0 form], applying L'Hospital rule again ,we get,

limx->0 2b*[-2cos2x - (sec2x+3tan2x*sec2x)] / 24 = 1/2 = > 2b[-2 -1] / 24 = 1/2 => -6b/24 = 1/2 => b = -2

from (A), we have , 2a = b => 2a = -2 => a = -1

Hence a =-1 & b = -2
7 0
2 years ago
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