Answer:
The number of ways this can be done is 1,260 ways
Step-by-step explanation:
In this question, we are asked to calculate the number of ways in which the letters of the word balloon can be arranged.
To do this, we take into consideration those letters that are repeated and the number of times repeated. The letters are l and o and are repeated two times each.
The number of ways = 7!/2!2! = 5040/4 = 1,260 ways
The answer is 2^12 = 4096.
Look at a tree diagram. With one spin there are two possible outcomes (branches). Every time you spin, each of the branches split into two more branches.
With 12 spins, first there are 2 branches, then 2*2, then 2*2*2, ... In the end it's 2^12
Yes, all of the rhombuses have 2 pairs of parallel side.
On a coordinate plane it is negetive 5
1/4(q-12) + 1/3(q+9), Then you must use the distributive property to get 1/q-3+1/3q+3. Then you simplify by combining like terms to get, 7/12q. You do not have any constants because they cross each other out.
