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3 years ago

A quarterback throws a football 40 yards in 4 seconds what is the average speed of the football?

Mathematics

2 answers:

hram777 [196]3 years ago

6 0

S=d/t

s=40/4

s=10

Therefore the average speed of the football is 10yd/s!

andrew-mc [135]3 years ago

3 0

Yards/seconds
40/4
10 yards per second

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Help me 3x+1/10=x-1/7 ok so I understand that I'm supposed to cross multiply so 1 x 10=10 7x3=21 so now do i do 21x-7? please He

koban [17]

Simplify both sides of the equation

3x+1/10 = x+ -1/7

Subtract x from both sides

3x+1/10 -x = x+ -1/7 -x

2x+1/10 = -1/7

Subtract 1/10 from both sides

2x+1/10 - 1/10 = -1/7 -1/10

2x= -17/70

Divide both sides by 2

2x/2 = -17/70/2

x= -17/140

decimal x will equal -0.121

Ask any questions you want and I hope that's help !

8 0

4 years ago

45 minutes ago

Alika [10]

Answer:

876889068

Step-by-step explanation:

8 0

3 years ago

Find the error in the solution, and then solve it correctly.

melamori03 [73]

We could find the error first, but if we solve the equation, we can compare our answers to find the error. So,

7x + 12 + 3x = 8

10x + 12 = 8

10x = -4

x = -4/10

x = -2/5.

When we compare the two, we see that our second line is vastly different, and we can easily isolate the mistake, finding that it occurs when they disregard the variable in the 3x term and subtract 8 by 3 rather than combining the terms 3x and 7x together.

8 0

3 years ago

Read 2 more answers

Find the equation of the line . Write in slope intercept form and in standard form. (SHOW YOUR SOLUTION)

AlladinOne [14]

Answer:

1) The slope-intercept and standard forms are $y = -5\cdot x + 1$ and $5\cdot x +y = 1$ , respectively.

2) The slope-intercept form of the line is $y = \frac{5}{2}\cdot x -\frac{9}{2}$ . The standard form of the line is $-5\cdot x +2\cdot y = -9$ .

3) The slope-intercept form of the line is $y = \frac{5}{2}\cdot x + 5$ . The standard form of the line is $-5\cdot x +2\cdot y = 10$ .

4) The slope-intercept and standard forms of the family of lines are $y = \frac{2}{7}\cdot x -\frac{c}{7}$ and $2\cdot x -7\cdot y = c$ , $\forall \,c \in \mathbb{R}$ , respectively.

5) The slope-intercept form of the line is $y = 2\cdot x-7$ . The standard form of the line is $-2\cdot x +y = -7$ .

Step-by-step explanation:

From Analytical Geometry we know that the slope-intercept form of the line is represented by:

$y = m\cdot x + b$ (1)

Where:

$x$ - Independent variable, dimensionless.

$m$ - Slope, dimensionless.

$b$ - y-Intercept, dimensionless.

$y$ - Dependent variable, dimensionless.

In addition, the standard form of the line is represented by the following model:

$a\cdot x + b \cdot y = c$ (2)

Where $a$ , $b$ are constant coefficients, dimensionless.

Now we process to resolve each problem:

1) If we know that $m = -5$ and $b = 1$ , then we know that the slope-intercept form of the line is:

$y = -5\cdot x + 1$ (3)

And the standard form is found after some algebraic handling:

$5\cdot x +y = 1$ (4)

The slope-intercept and standard forms are $y = -5\cdot x + 1$ and $5\cdot x +y = 1$ , respectively.

2) From Geometry we know that a line can be formed by two distinct points on a plane. If we know that $(x_{1},y_{1})=(1,-2)$ and $(x_{2},y_{2}) = (3,3)$ , then we construct the following system of linear equations:

$m+b= -2$ (5)

$3\cdot m +b = 3$ (6)

The solution of the system is:

$m = \frac{5}{2}$ , $b = -\frac{9}{2}$

The slope-intercept form of the line is $y = \frac{5}{2}\cdot x -\frac{9}{2}$ .

And the standard form is found after some algebraic handling:

$-\frac{5}{2}\cdot x +y = -\frac{9}{2}$

$-5\cdot x +2\cdot y = -9$ (7)

The standard form of the line is $-5\cdot x +2\cdot y = -9$ .

3) From Geometry we know that a line can be formed by two distinct points on a plane. If we know that $(x_{1},y_{1})=(-2,0)$ and $(x_{2},y_{2}) = (0,5)$ , then we construct the following system of linear equations:

$-2\cdot m +b = 0$ (8)

$b = 5$ (9)

The solution of the system is:

$m =\frac{5}{2}$ , $b = 5$

The slope-intercept form of the line is $y = \frac{5}{2}\cdot x + 5$ .

And the standard form is found after some algebraic handling:

$-\frac{5}{2}\cdot x+y =5$

$-5\cdot x +2\cdot y = 10$ (10)

The standard form of the line is $-5\cdot x +2\cdot y = 10$ .

4) If we know that $a = 2$ and $b = -7$ , then the standard form of the family of lines is:

$2\cdot x -7\cdot y = c$ , $\forall \,c \in \mathbb{R}$

And the standard form is found after some algebraic handling:

$-7\cdot y = -2\cdot x +c$

$y = \frac{2}{7}\cdot x -\frac{c}{7}$ , $\forall \,c\in\mathbb{R}$ (11)

The slope-intercept and standard forms of the family of lines are $y = \frac{2}{7}\cdot x -\frac{c}{7}$ and $2\cdot x -7\cdot y = c$ , $\forall \,c \in \mathbb{R}$ , respectively.

5) If we know that $(x,y) = (3,-1)$ and $m = 2$ , then the y-intercept of the line is:

$3\cdot 2 + b = -1$

$b = -7$

Then, the slope-intercept form of the line is $y = 2\cdot x-7$ .

And the standard form is found after some algebraic handling:

$-2\cdot x +y = -7$ (12)

The standard form of the line is $-2\cdot x +y = -7$ .

6 0

3 years ago

↓can somone answer this for 10 points↓

Gekata [30.6K]

Answer:

15P3 = 15!/ (15-3)! = 15*14*13*12! / 12! = 15*14*13

Step-by-step explanation:

When the seats are empty, there are a total of 15 people that can possibly sit in there. There will only be 1 person left.

When the 1st seat is taken there are now 14 people who can possibly sit on another chair. Same goes when 2 seaats are taken.

To find the total number of possibilities, we multiply together the possible number of people for seat 1, seat2, and seat 3.

Or, if we use stat, nPr = n! / (n-r)!

Meaning:

15P3 = 15!/ (15-3)! = 15*14*13*12! / 12! = 15*14*13

7 0

3 years ago