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BabaBlast [244]
3 years ago
9

Solve for w. k = 2b - 5w 3k

Mathematics
1 answer:
Zarrin [17]3 years ago
3 0
Theres an app called photomath that could easily solve problems like this
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What represents 2 less than 3 times a number
Lerok [7]

Answer:

What I think is

2-3n

or

3n-2

3 0
4 years ago
What is the product of the polynomial 2x^3 + 8x^2 + x + 3 times the<br> monomial x?
Elis [28]

Answer:

\huge\boxed{2x^4 + 8x^3 + x^2 + 3x}

Step-by-step explanation:

When we multiply a polynomial by a specific monomial, all terms in the polynomial get multiplied by the monomial.

So we can do this by term.

2x^3 \cdot x

Multiplying x by x to the something power will just increase the exponent on the x term by one (since powers are just x multiplied by itself). This means the exponent here will increase by 1, so this becomes 2x^4.

Same logic applies to the second term: 8x^2, raise the exponent by one, 8x^3.

For the third term, if there is no exponent on a term you can assume it's exponent is 1 (so x^1 in this case - as x^1=x). Again, using the same logic, this turns into x^2.

For the last term, when we multiply a constant by a variable, we get a term with a variable and a coefficient - the constant becomes the coefficient and the variable stays the variable. Therefore, 3 \cdot x = 3x.

Adding these terms all together gets us 2x^4 + 8x^3 + x^2 + 3x.

Hope this helped!

8 0
4 years ago
A circle is placed in a square with a side length of 16 ft , as shown below. Find the area of the shaded region.
Luda [366]

Answer:

55.04 ft²

Step-by-step explanation:

Calculate the area of the square, the area of the circle, then subtract the area of the circle from the area of the square.

Area of square = 16 x 16 = 256 ft²

Area of circle = \pir²

radius = 16 ÷ 2 = 8

⇒ Area of circle = 3.14 x 8² = 200.96 ft²

Shaded area = 256 - 200.96 = 55.04 ft²

7 0
2 years ago
Read 2 more answers
How many terms are in the expansion (a + b)20
Pavel [41]

Answer:

21 terms

Step-by-step explanation:

Number of terms = Exponent + 1 = 20 +1 = 21

5 0
3 years ago
Read 2 more answers
Use graphs and tables to find the limit and identify any vertical asymptotes of the function.
scZoUnD [109]

Answer:

The line x = 8 is our vertical asymptote

The limit of \frac{1}{x-8} as x approaches 8 from the left is negative infinity; -∞

Step-by-step explanation:

We have been given the following function;

\frac{1}{x-8}

Considering that the function is rational, it will defined everywhere on the real line except where the expression in the denominator will be 0;

That is the function will not be defined where;

x - 8 = 0

solving for x yields;

x = 8

The function will be approaching the vertical line x = 8 asymptotically, meaning that the function will never touch or cross this line. We can therefore say that,

The line x = 8 is our vertical asymptote for the given function

The limit of \frac{1}{x-8} as x approaches 8 from the left;

\lim_{x \to8^{-} }\frac{1}{x-8}

For x approaching 8 from the left, x which implies that x-8

The denominator will be a negative quantity approaching 0 from the left, that is -∞.

Thus;

\lim_{x \to8^{-} }\frac{1}{x-8} = -∞

Find the graph attached.

6 0
4 years ago
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