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nika2105 [10]
3 years ago
6

A piece of fabric costs $5.29 a yard. Which is an estimated cost of 16.3 yards of fabric?

Mathematics
2 answers:
alexandr1967 [171]3 years ago
7 0
B 5x16=84.6 I would probably choose b since it's closer
Marat540 [252]3 years ago
3 0
B. $80
$5.29 is about $5
16.3 yards is about 16
16 times 5 is 80
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William buys a basket of pomegranates on sale for $10 before tax. The sales tax is 17% What is the total price William pays for
Valentin [98]
$11.7 is the total price.
To solve. do 10 + (.17*10).
6 0
3 years ago
Please help with q 3, 4, 5 thnx!
dolphi86 [110]

Answer:

3. 7/12.

4. 7/5.

5. 1.

Step-by-step explanation:

The slope of a line can be obtained by taking the ratio of change in y-coordinate to that of x-coordinate. Mathematically, it is expressed as:

Slope = Δy /Δx

Δy = y2 – y1

Δx = x2 – x1

With the above formula in mind, let us answer the questions given above.

3. Point => (–8, –2) (4, 5)

x1 = –8

x2 = 4

Δx = x2 – x1

Δx = 4 – –8

Δx = 4 + 8

Δx = 12

y1 = –2

y2 = 5

Δy = y2 – y1

Δy = 5 – – 2

Δy = 5 + 2

Δy = 7

Slope = Δy /Δx

Slope = 7/12

4. Point => (3, –5) (8, 2)

x1 = 3

x2 = 8

Δx = 8 – 3

Δx = 5

y1 = –5

y2 = 2

Δy = y2 – y1

Δy = 2 – – 5

Δy = 2 + 5

Δy = 7

Slope = Δy /Δx

Slope = 7/5

5. Point => (–4, –5) (4, 3)

x1 = –4

x2 = 4

Δx = x2 – x1

Δx = 4 – –4

Δx = 4 + 4

Δx = 8

y1 = –5

y2 = 3

Δy = y2 – y1

Δy = 3 – – 5

Δy = 3 + 5

Δy = 8

Slope = Δy /Δx

Slope = 8/8

Slope = 1

8 0
3 years ago
Greatest common factor of 8a^2 and 11
Ierofanga [76]

Answer:

1

Step-by-step explanation:

factor both into prime factors

8a^2=2×2×2×a×a

11=11

find common factors. only common factor is one.

7 0
3 years ago
The price of a television decreased from $275 to $190 during a clearance sale. Solve for the percent of decrease in the price. R
IRINA_888 [86]
Since we know 100% = 100
 Take $275 - $190 = $85 , and then use $85 x 100 divided by the amount of $
85 x 100 / 275 = 30.9 Round to the nearest tenths which will equal to 31%. So the answer is B.
6 0
3 years ago
Nikita ran a 5-kilometer race in 39 minutes (0.65 of an hour) without training beforehand. In the first part of the race, her av
algol [13]
First part of the race

speed1, s1 = 8.75 km/h
distance1 = 5 km - x
time 1 = 0.65 h - t 

Second part of the race

speed2, s2 = 6 km/h
distance2 = x
time2 = t

s2 = x/t = 6 ⇒ t = x / 6

s1 = [5 - x] / [0.65 - t] = 8.75

5 - x = 8.75 [0.65 - t]

5 -x = 8.75(0.65) - 8.75t

5 - x = 5.6875 - 8.75 (x/6)

5 - x = 5.6875 - 1.4583x

1.4583 x - x = 5.6875 - 5

0.4583 x = 0.6875

x = 0.6875 / 0.4583 = 1.5 
6 0
3 years ago
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