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elena-s [515]
3 years ago
13

A collection of 36 shirts and 42 jackets contains 842 buttons. A collection of 66 shirts and 77 jackets contains 137 buttons. Ea

ch shirt has the same number of buttons, and each jacket has the same number of buttons. How many buttons are there in a Fiona's Fashion shirt, and how many buttons are there in a jacket?
Mathematics
2 answers:
Vlada [557]3 years ago
8 0
There are 102 shirts. There are 979 buttons in all. There are 119 jackets in all. All to there are 8 buttons in a jacket
uranmaximum [27]3 years ago
4 0

Answer:



Step-by-step explanation:

Let x represent the number of buttons on shirts and y represent the number of buttons on jackets.

If 36 shirts and 42 jackets contain 842 buttons. This implies:

36x + 42y = 842 (1)

If 66 shirts and 77 jackets contain 137 buttons. This implies:

66x + 77y = 137 (2)

If you take the first equation: 36x + 42y = 842 and isolate the x, then you will have x = (842 - 42y) / 36

If you substitute x into the second equation:

66((842-42y)/36) + 77y = 137

→ 11(842-42y)/6 + 77y = 137

→ 11(842-42y) + 6(77y) = 137(6)

→ 9262 - 462y + 462y = 822

→ 9262 = 822 which reveals that the equations do not have a solution

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For f(x)=4x+1 and g(x)=x^2-5, find (g/f)(x)
ddd [48]

Answer:

(g/f)(x) =  \frac{g(x)}{f(x)}  =  \frac{ {x}^{2} - 5 }{4x + 1}

I hope I helped you^_^

3 0
3 years ago
A cone has a diameter of 8 units and a height of 8 units. units, and its volume is Its radius is volume of cubic units. If a sph
aev [14]

The above question is not complete because it was not written and arranged properly

Complete Question

1) A cone has a diameter of 8 units and a height of 8 units. Its radius is 4 units, and its volume is ______ cubic units.

2) A cylinder with the same height and radius as the cone will have a volume ______ of cubic units.

3) If a sphere has the same radius as the cylinder, its volume is ______the volume of the cylinder. Answer: 1) Volume of the cone = 134.04cubic units

2)Volume of the cylinder = 402.12cubic units

3) Volume of the sphere= 268.08 cubic units. Hence, if a sphere has the same radius as the cylinder, its volume is 2/3 times the volume of the cylinder.

Step-by-step explanation:

1) A cone has a diameter of 8 units and a height of 8 units. Its radius is 4 units, and its volume is ______ cubic units.

Volume of a cone = 1/3πr²h

h = 8 units

r = 4 units

Volume = 1/3 × π × 4² × 8

134.04cubic units

2) A cylinder with the same height and radius as the cone will have a volume ______ of cubic units.

Volume of a cylinder = πr²h

Height and radius is the same as that of the cones hence,

h = 8 units

r = 4 units

= π × 4² × 8

= 402.12cubic units.

3) If a sphere has the same radius as the cylinder, its volume is ______the volume of the cylinder.

Volume of a Sphere = 4/3πr³

r = radius of the cylinder = 4 units

Volume of a Sphere = 4/3 × π × 4³

= 268.08 cubic units.

From the above question, we are asked to compare the volume of the sphere with the volume of the cylinder

Volume of the sphere : Volume of the cylinder

268.08 cubic units : 402.12 cubic units

268.08/402.12 = 2/3

Therefore, the volume of the sphere is 2/3 times the volume of the cylinder

6 0
2 years ago
Help me if your to cool for school...
tankabanditka [31]

Answer:

i think its set B..........

4 0
3 years ago
Read 2 more answers
Solve v=1/3 bh for b
katovenus [111]

Answer:

3v/h = b

Step-by-step explanation:

1/3 is a given fraction and to get rid of it you must multiply by it's reciprocal of 3/1 or 3. You will also multiply the other side by 3

3 * v = (1/3 bh) * 3     --> 3v = bh

divde both sides by h and you get 3v over h = b

3v/h = b

Hope this helps!

3 0
3 years ago
Read 2 more answers
A cell phone tower covers a circular area with a radius of 15 miles. You are at a location that is 11 miles west and 12 miles so
Murljashka [212]

Answer:

No you do not.

This is because we can use Pythagoras Theorem to show that our location sits outside the 15 mile radius of the cell tower.

To work is out you would write the equation

{11}^{2}  +  {12}^{2}  = 265

Then to work out the Hypotheses you would

\sqrt{265}  = 16.2788205961

Which proves that the location is outside of the 15 Mile radius of the cell tower.

3 0
3 years ago
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