To convert a mixed number into an improper fraction<span>, multiply the whole number by the denominator and add it to the numerator. This becomes the numerator of the </span><span>improper fraction, so 3 x 2 = 6 + 5 = 11 so, your answer should be 11/2</span>
Answer:
Option B.
Step-by-step explanation:
Option A. "The line constructed through point P that is parallel to line B."
Since parallel lines never intersect each other, a line intersecting line AB at point P will not be parallel.
Therefore, Option (A) is incorrect.
Option (B). "The line constructed through point P that is perpendicular to line AB."
Since the angle between line AB and a line constructed through point P has been given as 90°, line through point P will be perpendicular to AB.
Therefore, Option (B) is the answer.
Option C. "The line constructed through point P that intersects line AB at two different points."
Since, two perpendicular lines intersect each other at only one point, the line constructed from point P will not intersect line AB at two different points.
Therefore, Option C is not correct.
Start by looking at the vertex form of a quadratic function, f(x) = a(x - h)^2 + k. The variables h and k are the values of the vertex. Plug those in to get f(x) = a(x - 4)^2 + 5. To find the variable a, plug in the point given for the x and y values. So, you get (21) = a((8) - 4)^2 + 5. Solve for a algebraically, and you get a = 1. Finally, plug everything in and simplify the equation. You should get that the quadratic function is f(x) = x^2 - 8x + 21. Hope this helps!

Euclid's division lemma : Let a and b are two positive integers. There exist unique integers q and r such that
a = bq + r, 0
r < b
Or We can write it as,
Dividend = Divisor × Quotient + Remainder
<u>Work</u><u> </u><u>out</u><u>:</u>
Given integers are 240 and 228. Clearly 240 > 228. Applying Euclid's division lemma to 240 and 228,
⇛ 240 = 228 × 1 + 12
Since, the remainder 12 ≠ 0. So, we apply the division dilemma to the division 228 and remainder 12,
⇛ 228 = 12 × 19 + 0
The remainder at this stage is 0. So, the divider at this stage or the remainder at the previous age i.e 12

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