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Roman55 [17]
3 years ago
7

How Do You Solve (8x+7)^3?

Mathematics
2 answers:
marysya [2.9K]3 years ago
4 0
<span><span>(<span><span>8x</span>+7</span>)</span>*<span>(<span><span>8x</span>+7</span>)</span></span>*<span>(<span><span>8x</span>+7</span><span>)
</span></span><span>(<span><span>8x</span>+7</span>)</span><span>(<span><span><span>64<span>x^2</span></span>+<span>112x</span></span>+49</span><span>)
</span></span><span><span><span><span><span><span><span>(<span>8x</span>)</span><span>(<span>64<span>x^2</span></span>)</span></span>+<span><span>(<span>8x</span>)</span><span>(<span>112x</span>)</span></span></span>+<span><span>(<span>8x</span>)</span><span>(49)</span></span></span>+<span><span>(7)</span><span>(<span>64<span>x^2</span></span>)</span></span></span>+<span><span>(7)</span><span>(<span>112x</span>)</span></span></span>+<span><span>(7)</span><span>(49)
</span></span></span><span><span><span><span><span>512<span>x^3</span></span>+<span>896<span>x^2</span></span></span>+<span>392x</span></span>+<span>448<span>x^2</span></span></span>+<span>784x</span></span>+<span>343
</span>Answer:
<span><span><span>512<span>x^3</span></span>+<span>1344<span>x^2</span></span></span>+<span>1176x</span></span>+<span>343</span>

Andreyy893 years ago
3 0
I would use pascal's triangle
goes like this
0         1
1        1 1
2       1 2 1
3      1 3 3 1

the numbers on the left are the power of the binomial

baseically for the third power
(a+b)^3=1a^3b^0+3a^2+b^1+3a^1+b^2+1a^0+b^3

so you have
(8x+7)^3=1(8x)^3(7)^0+3(8x)^2(7)^1+3(8x)^1(7)^2+1(8x)^0(7)^3=
512x^3+1344x^2+1176x+343
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First you had to remove parenthesis first.

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Final answer \boxed{=-6}

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