If its 20% of a 64 ounce half gallon, you just need to find the last 80% of the half gallon. Since you know it is 64 ounces you can divide it by 5 which gives you 12.8. 12.8 would be 20% so you just subtract 12.8 from 64 ounces which gives you 51.2.
Let the length be x and the width be y the perimeter of the rectangle will be: 2x+2y=376 thus y=188-x thus the area will be: A(x)=x(188-x) A(x)=188x-x^2
For maximum Area A'(x)=0 from Area we shall have A'(x)=188-2x=0 solving for x we get: x=94 thus the width will be: 188-94=94 thus for maximum area the length=94 ft and width=94 ft Area=94*94=8836 ft^2 thus the answer is: <span>c. 94 x 94; 8836ft </span>
