Question

Mr. West is standing on a cliff that is 25 1/5meters above the surface of the ocean. He spots a dolphin that is 2 3/5 meters under the water. What was the total distance from Mr. West to the dolphin?

Answer 1

Answer:

Total distance from Mr. West to dolphin $=27\frac{4}{5}\ meters$

Step-by-step explanation:

Height of cliff on which Mr. West is standing above the surface of ocean =$25 \frac{1}{5} \ meters$

Mr. West spot the dolphin under the water at a depth of =  $2\frac{3}{5} \ meters$

∴ Total distance from Mr. West to dolphin=$(25 \frac{1}{5}+2\frac{3}{5})\ meters$

Adding mixed numbers

$(25 \frac{1}{5}+2\frac{3}{5})$

Adding whole numbers first.

$=25+2+\frac{1}{5}+\frac{3}{5}\\=27+\frac{1}{5}+\frac{3}{5}$

Adding fractions by taking LCD.

$=27+\frac{1+3}{5}\\=27+\frac{4}{5}\\=27\frac{4}{5}\ meters$