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3 years ago

Which function represents the cost of a pizza with n Toppings

Mathematics

2 answers:

ikadub [295]3 years ago

8 0

15 - 13.50 = 1.50

So each extra topping after the 1st is 1.50

C(n) = 12+ (n-1) 1.5

we use n-1 since the 1st topping is included in the 12 dollar price.

Choice B

alukav5142 [94]3 years ago

7 0

Correct answer is B... You can plug in values for n. Plug in 1 for n and the out put is 12. Plug in 2 for n and the output is 13.5

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A girl ran from her home to a store at the rate of 6 mph, and she walked back home at the rate of 4 mph. if it took 15 minutes f

viva [34]

Home is 0.6 miles away from the store

How to solve such time related questions?

The key concept for solving such questions is the relationship between speed, distance and time.

The relationship between them is Distance = Speed x Time

Given:-

Total time taken by girl to complete the trip = 15 minutes = $\frac{1}{4}$ hours

Speed while riding going = 6 miles per hour

Speed while coming back = 4 miles per hour

Total time taken by girl =

Time taken while going + Time taken while coming back - (1)

Let x be distance from home to store

$\frac{x}{6}$ = Time taken while going

$\frac{x}{4}$ = Time taken while coming back

Substituting in (1) we get

$\frac{1}{4} = \frac{x}{6} + \frac{x}{4}$

$\frac{1}{4} = \frac{2x + 3x}{12}$

$\frac{1}{4} = \frac{5x}{12}$

$x= \frac{12}{20}$

x = 0.6 miles

Thus home is 0.6 miles away from the store

Learn more about time related here :

brainly.com/question/12759408

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2 years ago

Find the sum.<br> 5<br> 2a<br> a? + 2a + 1<br> +<br> a2 + 4a + 3

Salsk061 [2.6K]

$\frac{2a}{a^2+2a+1}+\frac{5}{a^2+4a+3}$

Factor the denominators.

$\frac{2a}{\left(a+1\right)^2}+\frac{5}{\left(a+1\right)\left(a+3\right)}$

Adjust fractions based on LCM.

$\frac{2a\left(a+3\right)}{\left(a+1\right)^2\left(a+3\right)}+\frac{5\left(a+1\right)}{\left(a+1\right)^2\left(a+3\right)}$

Denominators are same, so add the fractions.

$\frac{2a\left(a+3\right)+5\left(a+1\right)}{\left(a+1\right)^2\left(a+3\right)}$

Expand the numerator.

$\frac{2a^2+11a+5}{\left(a+1\right)^2\left(a+3\right)}$

5 0

3 years ago

Read 2 more answers

Find the exact trigonometric ratios for the angle x whose radian measure is given. (if an answer is undefined, enter undefined.)

Inga [223]

Given the angle $\frac{3\pi}{4}$

angle $\frac{3\pi}{4}$ is equivalent to angle 135 degrees and angle 135 degrees is equvalent to angle 45 degrees in the second quadrant, thus sine is positive but cosine and tangent are negative.

$\sin \frac{3\pi}{4} =\sin \frac{\pi}{4} = \frac{1}{ \sqrt{2} } \\ \\ \csc\frac{3\pi}{4}= \frac{1}{\sin\frac{3\pi}{4}} = \frac{1}{\frac{1}{ \sqrt{2} }} = \sqrt{2} \\ \\ \cos\frac{3\pi}{4} =-\cos \frac{\pi}{4} = -\frac{1}{ \sqrt{2} } \\ \\ \sec\frac{3\pi}{4}= \frac{1}{\cos\frac{3\pi}{4}} = \frac{1}{-\frac{1}{ \sqrt{2} }} =- \sqrt{2} \\ \\ \tan\frac{3\pi}{4} =-\tan \frac{\pi}{4} = -1 \\ \\ \cot\frac{3\pi}{4}= \frac{1}{\tan\frac{3\pi}{4}} = \frac{1}{-1} =- 1$

8 0

3 years ago

Compare the functions represented by the ordered pairs:

mel-nik [20]

We are given

Set A: {(5,1), (4,4), (3,9), (2,16), (1,25)}

We can see that for each x value of the set is increasing exponentially.

y=(6-5)^2 = (1)^2 = 1

y=(6-4)^2 = (2)^2 = 4

y=(6-3) = (3)^2 = 9

y=(6-2)^2 = (4)^2 = 16

y=(6-1)^2 = (5)^2 = 25.

For set B:

Set B: {(1,-5), (2,-3), (3,-1), (4,1), (5,3)}

It's simply linear function as diffrences of y values are constant that is 2.

y = 2(1) -7 = 2-7 = -5

y = 2(2) -7 = 4-7 = -3

y = 2(3) -7 = 6-7 = 1

y = 2(4) -7 = 8-7 = 1

y = 2(5) -7 = 10-7 = 3.

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3 years ago

Read 2 more answers

Find the fifth term of the arithmetic sequence in which t1 = 3 and tn = tn-1 + 4. A) 5 B) 7 C) 19 D) 23 2) Find the tenth term o

Sergeu [11.5K]

We know that

Part a) <span>Find the fifth term of the arithmetic sequence in which t1 = 3 and tn = tn-1 + 4
t1=3
t2=t1+4----> 3+4-----> 7
t3=t2+4-----> 7+4----> 11
t4=t3+4-----> 11+4---> 15
t5=t4+4-----> 15+4---> 19

the answer Part a) is 19

Part b) </span><span>Find the tenth term of the arithmetic sequence in which t1 = 2 and t4 = -10

we know that
tn=t1+(n-1)*d-----> d=[tn-t1]/(n-1)
t1=2
t4=-10
n=4
find the value of d
d=[-10-2]/(4-1)-----> d=-12/3----> d=-4
find the </span>tenth term (t10)
t10=t1+(10-1)*(-4)----> t10=2+9*(-4)----> t10=-34

the answer Part b) is -34

Part c) <span>Find the fifth term of the geometric sequence in which t1 = 3 and tn = 2tn-1
t1=3
t2=2*t1----> 2*3----> 6
t3=2*t2----> 2*6----> 12
t4=2*t3-----> 2*12---> 24
t2=2*t4----> 2*24----> 48

the answer Part c) is 48</span>

3 0

4 years ago