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Elanso [62]
3 years ago
10

What should be the next letter in the following series? A z e b i y o _ ?_

Mathematics
1 answer:
Juliette [100K]3 years ago
3 0

Answer:  c

<u>Step-by-step explanation:</u>

Notice the pattern (vowel, consonant, vowel, consonant):

A: first vowel            z: last consonant

e: second vowel                                        b: first consonant      

i: third vowel             y: second to the last consonant

o: fourth vowel                                           <u>c: second consonant</u>

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Answer:

(B) P(B)=\dfrac{16}{31}

Step-by-step explanation:

From the Venn diagram, n(AUB)=31

The given probabilities in the option are calculated below:

P(A)=\dfrac{21}{31}\\\\P(B)=\dfrac{16}{31}\\\\P(A|B)=\dfrac{P(A\cap B)}{P(B)}= \dfrac{6/31}{16/31} =\dfrac{6}{16}=\dfrac{3}{8} \\\\P(B|A)=\dfrac{P(B\cap A)}{P(A)}= \dfrac{6/31}{21/31} =\dfrac{6}{21}=\dfrac{3}{7}

The only correct option is the probability of B which is \frac{16}{31}

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Solve for x and y in the system of equation<br>3x²+4y=17 <br>2x²+5y=2<br>I'll mark brainliest​
Novay_Z [31]

Answer:

x=\pm \sqrt{11} \\y=-4.

Step-by-step explanation:

\left \{ {{3x^2+4y=17} \atop {2x^2+5y=2}} \right. \\\\Then\\\\\left \{ {{2 \times (3x^2+4y)=2 \times 17} \atop {3\times(2x^2+5y)=3\times2}} \right. \\\\\left \{ {{6x^2+8y=34 \quad (1)} \atop {6x^2+15y=6\quad (2)}} \right.\\\\(1)-(2) \Rightarrow -7y=28 \Rightarrow y =-4.\\Since \: \:  2x^2+5y=2 \Rightarrow 2x^2=2-5y\\\Rightarrow 2x^2=2+20=22\\\Rightarrow x^2=22:2=11\\\Rightarrow x=\pm \sqrt{11}.

7 0
2 years ago
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Answer:

v = -52

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