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Rudiy27
3 years ago
15

A player of a video game is confronted with a series of 4 opponents and an 80% probability of defeating each opponent. Assume th

at the results from opponents are independent (and that when the player is defeated by an opponent the game ends). (a) What is the probability that a player defeats all 4 opponents in a game? Upper P equals left-parenthesis 0.8 right-parenthesis Superscript 4 Baseline equals 0.4096 (b) What is the probability that a player defeats at least 2 opponents in a game? Upper P equals 1 minus 0.2 minus 0.8 times 0.2 equals 0.64 (c) If the game is played 3 times, what is the probability that the player defeats all 4 opponents at least once? Probability defeats all 4 in a game = 0.84 = 0.4096. Probability defeats all four at least once = 1 – (1 – 0.4096)3 = 0.7942.
Mathematics
1 answer:
hram777 [196]3 years ago
8 0

Answer:

idk

Step-by-step explanation:

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QUESTION A

The given inequality is  

x-1\:>\:5

Add 1 to both sides of the inequality to obtain;

x\:>\:5+1

x\:>\:6

Answer: 2. x\:>\:6, open dot at 6 and shaded to the right.(A)

QUESTION B.

The given inequality is 2x \le 6.

Divide both sides by 2;

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QUESTION C

The given inequality is x-7\:>\:-4

Add 7 to both sides to get;

x\:>\:-4+7

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Answer: 7. x\:>\:3, open dot at 3 and shaded to the right.(C)

QUESTION D

We want to solve;

-2x \:

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x \:>\:\frac{6}{-2}

x \:>\:-3

Answer; 3. x \:>\:-3 Open dot at -3 and shaded to the right. (D)

QUESTION E

We have  

4\:

Divide through by -4 and reverse the sign.

\frac{4}{-4}\:>\:x

-1\:>\:x

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x\:

Answer: 6. x\: open dot at -1, and shaded to the left(E)

QUESTION F

The given inequality is -2x+3\:

Add -3 to both sides to get;

-2x\:

-2x\:

Divide both sides of the inequality by -2 and reverse the sign;

x\:>\:5

Answer:9. x\:>\:5, open dot at 5 and shaded to the right(F)

QUESTION G

The given  inequality is

5x+1\ge11

5x\ge11-1

5x\ge10

Divide by 5

x\ge2

Answer ; 10. x\ge2, closed dot at 2 and shaded to the right(G)

QUESTION H

We have 3(x+4)\:>\:8x-6

Expand the bracket to get;

3x+12\:>\:8x-6

Group similar terms to get;

3x-8x\:>\:-6-12

Simplify

-5x\:>\:-18

Divide through by -5 and reverse the sign;

x\:

Answer: 1. x\: Open dot at 18/5 and shaded to the left(H)

QUESTION I

We have -3x+4\:.

-3x+x\:

-2x\:

Divide by -2 and reverse the sign;

x\:>\:1

Answer: 8. x\:>\:1, open dot at 1 and shaded  to the right(I)

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Expand the bracket to get;

-2x+8\:>\:5-x-2

Group like terms to get;

-2x+x\:>\:5-2-8

-x\:>\:-5

Divide by -1 and reverse the sign to get;

x\:

Answer; 4. x\:, open dot at 5 and shaded to the left.(J)

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