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Murrr4er [49]
3 years ago
6

1_9,644=100,000 to the nearest ten thousand

Mathematics
1 answer:
laiz [17]3 years ago
7 0
119,644 is the answer I believe
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n 2000 the population of a small village was 2,400. With an annual growth rate of approximately 1.68%, compounded continuously,
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Answer:

The population would be 3358

Step-by-step explanation:

Since, exponential growth function if the growth is compound continuously,

A = Pe^{rt}

Where,

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r = growth rate per period,

t = number of periods,

Given,

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Number of years from 2000 to 2020, t = 20,

Thus, the population in 2020,

A=2400 e^{0.0168\times 20}

=2400 e^{0.336}

= 3358.4136

\approx 3358

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3 years ago
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