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zvonat [6]
4 years ago
13

Use the information about nutrition on page 173 to explain how linear equations can be used in nutrition. Explain how you could

use the Nutrition Information labels on packages to limit your fat intake.
Mathematics
1 answer:
alex41 [277]4 years ago
7 0

Answer: By looking at several aspects of the Nutrition Information, such as the Serving Size, Total Calories and the Nutrition Terms, you can limit how much fat your body takes in. For instance, looking at the serving size is the first thing you should do. By looking at the serving size, you can determine how much calories, vitamins, cholesterol, etc you will take in. The next step is to check the total amount of calories the food/drink has. To truly limit your fat intake, you want to pay attention how much calories the food is and compare it to how much you ate/drank today. Lastly make sure you pay attention on how much cholesterol and saturated fat to minimize your fat intake.

If you need more information, visit this website https://www.eatright.org/food/nutrition/nutrition-facts-and-food-labels/the-basics-of-the-nutrition-facts-label

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17.5% of 360 help please!!
earnstyle [38]

Answer:

its 63


             hope this helps

Step-by-step explanation:


8 0
4 years ago
Read 2 more answers
In the expansion (ax+by)^7, the coefficients of the first two terms are 128 and -224, respectively. Find the values of a and b
madam [21]

Answer:

a = 2, b = 3.5

Step-by-step explanation:

Expanding (ax+by)^7 using Binomial expansion, we have that:

(ax+by)^7 =

(ax)^7(by)^0 + (ax)^6(by)^1 + (ax)^5(by)^2 + (ax)^4(by)^3 + (ax)^3(by)^4 + (ax)^2(by)^5 + (ax)^1(by)^6 + (ax)^0(by)^7

= (a)^7(x)^7+ (a)^6(x)^6(b)(y) + (a)^5(x)^5(b)^2(y)^2 + (a)^4(x)^4(b)^3(y)^3 + (a)^3(x)^3(b)^4(y)^4 + (a)^2(x)^2(b)^5(y)^5 + (a)(x)(b)^6(y)^6 + (b)^7(y)^7\\\\\\= (a)^7(x)^7+ (a)^6(b)(x)^6(y) + (a)^5(b)^2(x)^5(y)^2 + (a)^4(b)^3(x)^4(y)^3 + (a)^3(b)^4(x)^3(y)^4 + (a)^2(b)^5(x)^2(y)^5 + (a)(b)^6(x)(y)^6 + (b)^7(y)^7

We have that the coefficients of the first two terms are 128 and -224.

For the first term:

=> a^7 = 128

=> a = \sqrt[7]{128}\\ \\\\a = 2

For the second term:

a^6b = -224

b = \frac{-224}{a^6}

b = \frac{-224}{2^6} \\\\\\b = \frac{-224}{64} \\\\\\b = 3.5

Therefore, a = 2, b = 3.5

5 0
3 years ago
You have prizes to reveal! Go to your garne
pickupchik [31]
1 ton = 2,000 pounds

3 tons = $3,840
2,000 lbs = $3,840
Divide by 2,000
1 lbs = $1.92

The price per pound is $1.92
5 0
3 years ago
Only need help on number 5 and 6
Alborosie

5) since (x-a)^2+(y-b)^2=r^2

plug in (-5,2) as (a,b) and r=3

Making the equation:

(x+5)^2+(y-2)^2=9

6) (x-0)^2+(y-0)^2=r^2

since we have (0,5)

0^2+5^2=r^2

Final equation: x^2+y^2=25

5 0
3 years ago
Solve using appropriate property:<br> 3/8 × -4/5 + 7/9 × 3/8 (-3/8 × 8/10)
bazaltina [42]

Answer:

Exact Form:

- 31/80

Decimal Form:

-0.3875

Step-by-step explanation:

hope this helps

sorry if wrong

7 0
2 years ago
Read 2 more answers
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