The children between ages of 2 and 5 watch an average of 25 hours of TV per week. Assume that standard deviation is 3 hours of T V per week, if a sample 20 children between ages of 2-5 are randomly selected with the mean sample of 26.3. Find the probability that the mean number of hours they watch TV is greater than 2.6 hours.
1 answer:
Answer:
the probability that the mean number of hours they watch TV is greater than 26.3 hours is 0.034
Step-by-step explanation:
<u>Last part of the question is wrong. It should be:</u>
Find the probability that the mean number of hours they watch TV is greater than 26.3 hours.
P('the mean number of hours the children between ages of 2 and 5 watch TV' >26.3 hours) = P(t>t*) where
t* is the t-score of 26.3 hours. It can be found using the equation:
where
M is the mean number of hours the children between ages of 2 and 5 watch TV (25 hours) s is the standard deviation (3 hours) N is the sample size (20) : ≈1.938
Corresponding p-value with 19 degrees of freedom: P(t>1.938) is ≈ 0.034
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