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4 years ago

Is there a possibility that there is a place on earth where earthquake have not been experienced?

Geography

2 answers:

satela [25.4K]4 years ago

8 0

Answer:

It occurs, but the frequency or motion is not enough to affect anything, hence the attention of the people.

Explanation:

I've lived in my hometown for 18 years and no appearance of terrible earthquake recorded according to my memory.

r-ruslan [8.4K]4 years ago

7 0

Answer:

I don't think so

Explanation:

this is because the earth keeps on moving and hence causing plates to move due to tectonic movements.

also due to the human activities such as use of explosives trigger earth quakes

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3 years ago

HURRY!!!!! BRAINLIEST!!!!!

alexandr1967 [171]

I think the answer is visual learning

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3 years ago

As part of a territorial conflict in Bosnia, ethnic Croats expelled, imprisoned, or killed the Muslim people with whom they had

klio [65]

Answer:d.ethnic cleansing

Explanation:

Ethnic cleansing can be defined as the foreceful removal of unwanted ethnic comnunity or racial group from a given territory by more powerful ethnic group. This is done with an intent of making the nation or region ethnically homogeneous. This is done by forced migration, homicides and genocidal rapes.

The given situation of Bosnia is an example of ethnic cleansing. The Muslim community is the ethnically inferior group which is being treated badly so that the community can be irradiacted from Bosnia.

7 0

3 years ago

What is the value of X6? <br><br> Show the solution.

wariber [46]

Answer : The value of $x_6$ is $\sqrt{7}$ .

Explanation :

As we are given 6 right angled triangle in the given figure.

First we have to calculate the value of $x_1$ .

Using Pythagoras theorem in triangle 1 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_1)^2=(1)^2+(1)^2$

$x_1=\sqrt{(1)^2+(1)^2}$

$x_1=\sqrt{2}$

Now we have to calculate the value of $x_2$ .

Using Pythagoras theorem in triangle 2 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_2)^2=(1)^2+(X_1)^2$

$(x_2)^2=(1)^2+(\sqrt{2})^2$

$x_2=\sqrt{(1)^2+(\sqrt{2})^2}$

$x_2=\sqrt{3}$

Now we have to calculate the value of $x_3$ .

Using Pythagoras theorem in triangle 3 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_3)^2=(1)^2+(X_2)^2$

$(x_3)^2=(1)^2+(\sqrt{3})^2$

$x_3=\sqrt{(1)^2+(\sqrt{3})^2}$

$x_3=\sqrt{4}$

Now we have to calculate the value of $x_4$ .

Using Pythagoras theorem in triangle 4 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_4)^2=(1)^2+(X_3)^2$

$(x_4)^2=(1)^2+(\sqrt{4})^2$

$x_4=\sqrt{(1)^2+(\sqrt{4})^2}$

$x_4=\sqrt{5}$

Now we have to calculate the value of $x_5$ .

Using Pythagoras theorem in triangle 5 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_5)^2=(1)^2+(X_4)^2$

$(x_5)^2=(1)^2+(\sqrt{5})^2$

$x_5=\sqrt{(1)^2+(\sqrt{5})^2}$

$x_5=\sqrt{6}$

Now we have to calculate the value of $x_6$ .

Using Pythagoras theorem in triangle 6 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_6)^2=(1)^2+(X_5)^2$

$(x_6)^2=(1)^2+(\sqrt{6})^2$

$x_6=\sqrt{(1)^2+(\sqrt{6})^2}$

$x_6=\sqrt{7}$

Therefore, the value of $x_6$ is $\sqrt{7}$ .

5 0

3 years ago

The isotope silicon 32 decays into phosphorus 32. Silicon 32 has a half-life of 170 years and can be used to find the age of roc

eduard

Answer:

B and C

Explanation:

B. In a given rock sample, the amount of Silicon-32 isotopes gets divided in half about every 170yrs.

This is the concept of half-life. Half life is the time take for half of a radioactive isotope to disintegrate. The shorter the half life the faster the isotope disintegrates.

From the question, we were told that it would take 170yrs for half of the isotope of Silicon to disintegrate to Phosphorus. This is the half life.

C. The half life can be used to determine the amount of Si-32 that has decayed from the time closure temperature was reached.

The closure temperature is very important in radioactivity. It is the temperature at which a system has cooled and there is no resulting disintegration of parent and daughter isotopes.

From first order kinetics, we know that the rate at which radioactive elements decay at any time is directly proportional to the number of radioactive atoms present. A knowledge of the half life helps to figure out the number of atoms that has decayed in time.

5 0

4 years ago