different between A and B
=30-(-30)
=60
position of C from A or B
=(60÷3)×2
=40
possible value of c
=-30+40
=10
possible value of c
=30-40
=-10
Answer:
Step-by-step explanation:
b) 1- scale factor from the first map to the second map:
= 1.33
2- landmark on the first map is a triangle with side lengths of 3 mm, 4 mm, and 5 mm.
Side lengths of the landmark on the second map
Divide the length by scale factor:
side lengths of 3 mm:
= 2.25 mm
side lengths of 4 mm:
= 3.007 mm
side lengths of 5 mm:
= 3.75 mm
Percent increase=increase/original times 100
increase=26-21=5
original=21
so
5/21 times 100=0.23809523809523809523809523809524 times 100=23.809523809523809523809523809524
round
24%
so 24% increase
Option 1:
<span>Measuring the heights of every fiftieth person on the school roster to determine the average heights of the boys in the school
</span>
Comment: this might not be a good idea for fairness as we only wish to determine average height of the boys. Taking a group of 50 people randomly, might not give us the same number of boys every time.
Option 2:
<span>Calling every third person on the soccer team’s roster to determine how many of the team members have completed their fundraising assignment
Comment: The context doesn't seem to need a sampling. The number of players in a soccer team is considerably small. We can find exact data by asking in person.
Option 3:
</span><span>
Observing every person walking down Main Street at 5 p.m. one evening to determine the percentage of people who wear glasses
</span>
Comment: To get a more accurate result and fairer sampling, the period of observing could have been longer, for example, observing for 12 hours on that day, or an alternative is to observe at 5 pm for 7 days in a row. It could happen that no one walking down the Main street precisely at 5 pm wears glasses, or it could happen the other way around.
Option 4:
<span>Sending a confidential e-mail survey to every one-hundredth parent in the school district to determine the overall satisfaction of the residents of the town taking a poll in the lunch room (where all students currently have to eat lunch) to determine the number of students who want to be able to leave campus during lunch.
Comment: This sampling does fairly represent the population, although it might be an idea to scale down the sample population, i.e. every fiftieth parent.
Answer: Option 4</span>
The correct answer would be C. Hope this helps=)