Answer:
The proportion of student heights that are between 94.5 and 115.5 is 86.64%
Step-by-step explanation:
We have a mean 
and a standard deviation 
. For a value x we compute the z-score as 
, so, for x = 94.5 the z-score is (94.5-105)/7 = -1.5, and for x = 115.5 the z-score is (115.5-105)/7 = 1.5. We are looking for P(-1.5 < z < 1.5) = P(z < 1.5) - P(z < -1.5) = 0.9332 - 0.0668 = 0.8664. Therefore, the proportion of student heights that are between 94.5 and 115.5 is 86.64%
I would say it is 248,700
Answer:
Hey mate......
Step-by-step explanation:
This is ur answer.....
288 × 232 = 66,816
hope it helps,
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The dot on -1 is open, so the number -1 is not included. You need all real numbers greater than -1.
Answer: D
360.
A general rule of thumb when dealing with questions like these is using the following equation:
(number of numbers) x (mean) = sum of numbers
Proof/Example: 7, 10, 13
There are 3 numbers here and the mean is 10. Multiply them together and you will get 30, just as you will get 30 from adding them together.
In this case, there are 4 numbers and the mean is 90, so 4 x 90 = 360.
