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FrozenT [24]
3 years ago
7

How to solve this??? e^(2x) - e^x = 6

Mathematics
1 answer:
Ray Of Light [21]3 years ago
5 0
e^{2x}-e^x=6
(e^x)^2-e^x-6=0
(e^x-3)(e^x+2)=0

e^x=3
e^x=-2

therefore x=\ln3 and x=\ln-2
because \ln-2 doesn't exist, the only solution to your equation is x=\ln3
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bogdanovich [222]
· Author has 184 answers and 67.6K answer views
Let the number be (10 x + y)

Then, 10 x + y = 3 * (x + y) (given)

Or, 10 x + y = 3 x + 3 y

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Or, 7x = 2 y

Or, x = 2 y / 7 ( Eq. 1)

Also, 10 x + y + 45 = 10 y + x ( given)

Or, 10 x - x = 10 y - y - 45

Or, 9 x = 9 y - 45 ( Eq. 2)

Substituting the value of x from (Eq. 1) in (Eq. 2), we have:

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Answer

Check:

Sum of the digits = 2 + 7 = 9

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