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Irina-Kira [14]
4 years ago
6

Find a polynomial function of degree 4 with -1 as a zero of multiplicity 3 and 0 as a zero of multiplicity 1.

Mathematics
1 answer:
almond37 [142]4 years ago
7 0
y=(x-(-1))(x-(-1))(x-(-1))(x-0)
\\y=(x+1)(x+1)(x+1)x
\\y=(x+1)^3x
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What is the value of the expression 4 times(5-2) times 2
Vlada [557]
So you use PEMDAS or order of simplication or operations
Parenthases
exponents
multilication or division
subtraction or aditon
so
parenthasees first so we have (5-2)
5-2=3

now we have
4 times 3 times 2
multiply4 times 3=12
now we have
12 times 2
12 times 2=24
answer is 24

4 0
3 years ago
Read 2 more answers
8.
Anni [7]

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6 0
3 years ago
Could anyone help me with this problem! Please do, thank you.
Alina [70]

                                         P  =  R - C
a).
Add 'C' to each side:      P + C  =  R

b). Write the values of 'P' and 'C' into the equation:

                                         
P  +  C  =  R

                                  ($350) + ($529)  =  R

                                            $879  =  R 









6 0
4 years ago
The law of conversation of momentum explains that the momentum after a collision is?
shepuryov [24]

Answer:

is neither lost or gained

Step-by-step explanation:

The law of conversation tells us that energy can't be created or destroyed. So, the total energy of an isolated system should be constant.

This also works for momentum. When 2 objects collide, their total momentum will not change. Some of the energy can be transferred which change the momentum of individual object, but not the sum/total.

3 0
4 years ago
. Write the equation for a circle with center (0, −4) and radius 8.
balu736 [363]
<h2>Equation for a circle with center (0, −4) and radius 8 is x²+y²+8y-48 = 0</h2>

Step-by-step explanation:

Equation of circle with (h,k) as center and radius r is given by,

          (x-h)²+(y-k)² = r²

Here we need to find equation for a circle with center (0, −4) and radius 8.

Center = (h,k) = (0, −4)

Radius = r = 8

Substituting in equation

              (x-h)²+(y-k)² = r²

               (x-0)²+(y-(-4))² = 8²

               x²+(y+4)² = 64

                x²+y²+8y+16 = 64

                x²+y²+8y-48 = 0

Equation for a circle with center (0, −4) and radius 8 is x²+y²+8y-48 = 0

8 0
3 years ago
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