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Mrac [35]
3 years ago
15

Factor completely 49q^4 - 4​

Mathematics
2 answers:
nadezda [96]3 years ago
7 0

Step-by-step explanation:

49q^4-4

(7q^2)^2-(2)^2

(7q^2+2)(7q^2-2)

Brrunno [24]3 years ago
5 0

Rewrite it in the form a^2 - b^2, where a = 7q^2 and b = 2

(7q^2)^2 - 2^2

Use the Difference of Squares; a^2 - b^2 = (a + b)(a - b)

<u>= (7q^2 + 2)(7q^2 - 2)</u>

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Serjik [45]

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3 0
3 years ago
Rewrite the following logarithmic expression as an exponential expression
Mumz [18]

\huge{ \mathrm{  \underline{ Answer }\:  \:  ✓ }}

The logarithmic expression for the given exponential expression is :

\large\boxed{ \mathrm{ log_{4}(b )= a}}

_____________________________

\mathrm{ ☠ \: TeeNForeveR \: ☠}

4 0
3 years ago
The polynomial function f(x) is a fourth degree polynomial. Which of the following could be the complete list of the roots of f(
cluponka [151]

Answer:

the answer is A

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Juan invest $3700 in a simple interest account at a rate of 4% for 15 years
OleMash [197]

<em><u>Question:</u></em>

Juan Invest $3700 In A Simple Interest Account At A Rate Of 4% For 15 Years. How Much Money Will Be In The Account After 15 Years?

<em><u>Answer:</u></em>

There will be $ 5920 in account after 15 years

<em><u>Solution:</u></em>

<em><u>The simple interest is given by formula:</u></em>

S.I = \frac{p \times n \times r }{100}

Where,

p is the principal

n is number of years

r is rate of interest

From given,

p = 3700

r = 4 %

t = 15 years

Therefore,

S.I = \frac{3700 \times 4 \times 15 }{100}\\\\S.I = 37 \times 4 \times 15\\\\S.I = 2220

<em><u>How Much Money Will Be In The Account After 15 Years?</u></em>

Total money = principal + simple interest

Total money = 3700 + 2220

Total money = 5920

Thus there will be $ 5920 in account after 15 years

8 0
3 years ago
Okay google how many pennies are in $25,000
GalinKa [24]
There are 2,500,000 pennies in $25,000
4 0
3 years ago
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