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STatiana [176]
3 years ago
6

What is 1/6 of $336 dollars. Can you please show me how to break it down

Mathematics
1 answer:
NeTakaya3 years ago
7 0

Answer:

56

Step-by-step explanation:

so what you do is take 1/6 and multiply it by 336 and you get 56 which would be 1/6 of 336

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The population of mosquitoes in a certain area increases at a rate proportional to the current population, and in the absence of
Alexandra [31]

Answer:

Population of mosquitoes in the area at any time t is:

P(t) =504,943.26  -104,943.26e^{0.693t}

Step-by-step explanation:

assume population at any time t = P(t)

population increases at a rate proportional to the current population:

⇒dP/dt ∝ P

 \implies \frac{dP}{dt} =kP----(1)

where k is constant rate at which population is doubled

solving (1)

ln|P(t)|=kt +C\\P(t)= e^{kt+C}\\P(t)=Ce^{kt}

t=0\\P(0) = P_{o}\\\implies C= P_{o}\\P(t) =P_{o}e^{kt}\\ ---- (2)

initial population = 400,000

population is doubled every week

                                                 ⇒P(1)=2P(0)

Using (2)

                                 P_{o}e^{k(1)} = 2P_{o} e^{k(0)}\\

                                            e^{k} =2\\k=ln|2|\\

In presence of predators amount is decreased by 50,000 per day

Then amount decreased per week = 350,000

In this case (1) becomes

\frac{dP}{dt}=kP-350,000\\\frac{dP}{dt} - kP=-350,000\\ ---(3)

solving (3) by calculating integrating factor

                                          I.F=e^{\int-k dt}

Multiplying I.F with all terms of (3)

e^{-kt}\frac{dP}{dt} - ke^{-kt}P =-350,000 e^{-kt}\\\frac{d}{dt}(e^{-kt}P) =  -350,000 e^{-kt}

Integrating w.r.to t

                         e^{-kt}P(t)= \frac{350,000e^{-kt}}{k} +C

                         P(t) =\frac{350,000}{k} +Ce^{kt}\\

                                          k=ln|2| =0.693

                          P(t) =504,943.26 + Ce^{0.693t}\\

at t=0

                        P(0) =504,943.26 + Ce^{0.693(0)}

                        400,000 =504,943.26 + C

                           C = -104,943.26

So, population of mosquitoes in the area at any time t is

                  P(t) =504,943.26  -104,943.26e^{0.693t}

6 0
3 years ago
GEOMETRY HELP Which of the following are dependent events?
lisabon 2012 [21]

Answer:

Option C

Step-by-step explanation:

A and B are said to be independent of

P(A intersection B) = P(A)*P(B).

Or if drawing is done with replacement, etc.

A) P(drawing a king) = 4/52 = 1/13

IF we replace again drawing a kind is the same 1/13

Hence independent

B) Coin flipping each toss is obviously independent of the other as prob of getting tail in a fair coin is 1/2 irrespective of the previous outcomes

C) Without replacement is not independent

Since first prob = 4/52 and second would be 3/51 not the same as before

D) Rolling a die is independent as getting a 2 in any throw is always the same.

C is answer

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