Question

Need some math help!!! Factor the polynomial by grouping: 12p^3 − 21 p^2 + 28p − 49

Answer 1

Answer:

$\left(4p-7\right)\left(3p^2+7\right)$

Step-by-step explanation:

$12p^3-21p^2+28p-49$

$\left(12p^3-21p^2\right)+\left(28p-49\right)$

$7\left(4p-7\right)$

$3p^2\left(4p-7\right)$

$7\left(4p-7\right)+3p^2\left(4p-7\right)$

$\left(4p-7\right)\left(3p^2+7\right)$

Answer 2

12p³ – 21p² + 28p – 49

3p²(4p–7) + 7(4p–7)

(4p–7)(3p+7)