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Svetllana [295]
3 years ago
5

Need some math help!!! Factor the polynomial by grouping: 12p^3 − 21 p^2 + 28p − 49

Mathematics
2 answers:
Andru [333]3 years ago
8 0

Answer:

\left(4p-7\right)\left(3p^2+7\right)

Step-by-step explanation:

12p^3-21p^2+28p-49

\left(12p^3-21p^2\right)+\left(28p-49\right)

7\left(4p-7\right)

3p^2\left(4p-7\right)

7\left(4p-7\right)+3p^2\left(4p-7\right)

\left(4p-7\right)\left(3p^2+7\right)

yan [13]3 years ago
8 0
12p³ – 21p² + 28p – 49

3p²(4p–7) + 7(4p–7)

(4p–7)(3p+7)
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see below

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(ii) Are sets A - B and B - A equal sets?

A-B= {9, 11, 13}

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