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lara [203]
4 years ago
13

What is the mode of 70 68 70 72 68 66?

Mathematics
1 answer:
fredd [130]4 years ago
4 0
What is the mode of 70 68 70 72 68 66? 69
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Hello everyone I need help with this worksheet it's ten problems answer the ones you know for me please it's homework.
Fed [463]

Answer:

1. Slope = -4/5

2. Slope = 2/3

3. Slope = 0

4. Slope = 3/-4

5. Slope = 7/-12

6. Slope = 1/2

7. Slope = -2/0 --> Undefined

8. Slope = 3/-2

9. Slope = 5/-4

10. Slope = 4/3

Step-by-step explanation:

Ok so I'm assuming that you want the slope for all the two points. Basically, the formula for slope is rise/run, or y2-y1/x2-x1. Solve using that. For example, for number 1, it would be:

10-2/1-11 = 8/-10 = -4/5

5 0
3 years ago
Three noncollinear points determine a triangle. How many triangles can be formed with 8 points, no three of which are collinear?
Nataliya [291]
Correct answer is A.

C^8_3= \frac{8\times7\times6}{3\times2\times1}=56
5 0
3 years ago
At a cat show, 60% of the cats had long hair. There were 168 cats with long hair in the show. How many cats were in the show?
abruzzese [7]
D
Do 60/100 x 168 on ur calculator and u get the answer
3 0
3 years ago
Read 2 more answers
HELP DUE AT 11:59!!!!!
faltersainse [42]

Answer:

lmk if u ended up with a retake or sum sorry nobody got bk to before it was due

5 0
3 years ago
Read 2 more answers
A sample of size 60 from one population of weights had a sample average of 10.4 lb. and a sample standard deviation of 2.7 lb. A
Olegator [25]

Answer:

z=  0.278

Step-by-step explanation:

Given data

n1= 60 ; n2 = 100

mean 1= x1`= 10.4;     mean 2= x2`= 9.7

standard deviation  1= s1= 2.7 pounds ;  standard deviation 2= s2 = 1.9 lb

We formulate our null and alternate hypothesis as

H0 = x`1- x`2 = 0 and H1 = x`1- x`2 ≠ 0 ( two sided)

We set level of significance α= 0.05

the test statistic to be used under H0 is

z = x1`- x2`/ √ s₁²/n₁ + s₂²/n₂

the critical region is z > ± 1.96

Computations

z= 10.4- 9.7/ √(2.7)²/60+( 1.9)²/ 100

z= 10.4- 9.7/ √ 7.29/60 + 3.61/100

z= 0.7/√ 0.1215+ 0.0361

z=0.7 /√0.1576

z= 0.7 (0.396988)

z= 0.2778= 0.278

Since the calculated value of z does not fall in the critical region so we accept the null hypothesis H0 = x`1- x`2 = 0  at 5 % significance level. In other words we conclude that the difference between mean scores is insignificant or merely due to chance.

3 0
3 years ago
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