Question

Please help me it’s due tomorrow and I really need help

Answer 1

Answer:

5 $\frac{1}{3}$, 10 $\frac{2}{3}$

Step-by-step explanation:

There is a common ratio r between consecutive terms, that is

$\frac{2}{3}$ ÷ $\frac{1}{3}$ = 1 $\frac{1}{3}$ ÷ $\frac{2}{3}$ = 2 $\frac{2}{3}$ ÷ 1 $\frac{1}{3}$ = 2

Thus to obtain a term in the sequence multiply the previous term by 2, thus

a₅ = $\frac{8}{3}$ × 2 = $\frac{16}{3}$ = 5 $\frac{1}{3}$

a₆ = $\frac{16}{3}$ × 2 = $\frac{32}{3}$ = 10 $\frac{2}{3}$