A bowl contains 3 red, 8 blue, and 7 black beads. Margaret randomly selects 3 beads one after the other without replacement. Fin

Question

drek231 [11]

3 years ago

5

A bowl contains 3 red, 8 blue, and 7 black beads. Margaret randomly selects 3 beads one after the other without replacement. Fin

d the probability of getting a red, blue, and black bead, in that order.

Mathematics

1 answer:

r-ruslan [8.4K] · Answer 1 · 2022-03-17T00:06:44+03:00

Total number of beads = 3 + 8 + 7 = 18. P(red) = total number of red/total number of beads = 3/18 = 1/6. P(blue) = total number of blue beads/total number of beads left after replacement = 8/17. P(black) = total number of black beads/total number of beads left after replacement = 7/16. Therefore P(red) = 1/6. P(blue) = 8/17. P(black) = 7/16.