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Setler [38]
3 years ago
8

There are 14 NBA teams who do not make

Mathematics
1 answer:
leva [86]3 years ago
8 0
In this situation, the order matters, since being 1st pick is not the same as being 2nd or 3rd. Therefore, there are 14 choices for the first pick, 13 remaining for the second pick, and 12 for the third pick. This is equivalent to the permutation 12P3.
12P3 =  \frac{12!}{(12-3)!} = 12(11)(10) = 1320 ways

(If order did not matter, this would use a combination.)

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i am greater than one-fourth but less than four tenths . i am a decimal rounded to the hundreds place. what number am i
artcher [175]
(0.25,0.40). Written in interval notation. It can be any number greater than 1/4 but less that 4/10. 
3 0
3 years ago
Read 2 more answers
Expand and simply following expression.<br> 5(n – m) +3(n – m)
Brilliant_brown [7]

Answer:

n = x \\ m = y \\ 5x - 5y + 3x - 3y = 8x - 8y = 8(x - y)

4 0
3 years ago
10. Point W bisects segment UV. Find UV if WV = 11% inches.​
Nuetrik [128]

The segment <u>UV = 22 1/4 inches</u>, using the segment addition postulate.

According to the segment addition postulate, a third point B will only be located on the line segment AC if and only if the equation AB + BC = AC is true for a line segment with two endpoints, A and C.

In the question, we are given that point W bisects segment UV.

We are asked to find UV if WV = 11 1/8 inches.

For the segment UV, if point W bisects it, then point W is on the segment, and by the segment addition postulate, we can write that UW + WV = UV.

Now, as we are given that W bisects UV, we can conclude that UW will be equal to WV.

Thus, we can write that UW = WV = 11 1/8 inches.

Substituting the values of UW and WV in the equation UW + WV = UV, we get:

11 1/8 + 11 1/8 = UV,

or, UV = 11 1/8 + 11 1/8,

or, UV = 89/8 + 89/8,

or, UV = 178/8,

or, UV = 89/4,

or, UV = 22 1/4.

Thus, the segment <u>UV = 22 1/4 inches</u>, using the segment addition postulate.

Learn more about the segment addition postulate at

brainly.com/question/2134445

#SPJ9

7 0
1 year ago
The Wall Street Journal Corporate Perceptions Study surveys readers and asks how each rats the quality of management and the rep
ololo11 [35]

Answer:

Step-by-step explanation:

\text{The data given for the quality measurement and other criteria can be seen below:}

Quality management      Excellent      Good      Fair      Total

Excellent                             40                   25         5             70

Good                                   35                    35        10            80

Fair                                       25                   10         15             50

Total                                    100                   70        30           200

The null and alternative hypothesis:

\mathbf{H_o: \text{the quality management and reputation are independent} }

\mathbf{H_a: \text{the quality management and reputation are not independent} }

The expected value is calculated by using the formula:

E=\dfrac{row  \ total \times column  \ total }{table \  total}

After using the formula to calculate the table above; we have:

The expected values of the data to be:

Quality management     Excellent         Good      Fair      Total

Excellent                            35                  24.5       10.5      70

Good                                  40                   28         1.2         80

Fair                                     25                  17.5        7.5         50

Total                                   100                  70        30           200

Degree of freedom = ( row - 1 ) × ( column -1 )

= (3 - 1 ) \times (3 -1)

= 2\times 2

=4

\text{The p-value at level of significance of 0.05 and degree of freedom of 4 =  }\mathbf{0.0019}

Decision rule: To reject the \mathbf{H_o} if the p-value is less than the ∝

Conclusion: We reject the \mathbf{H_o} and conclude that quality management and reputation are not independent.

(B)\text{The P-value here implies that in case that there is no dependence between the two ratings, }\text{the probability that they will seem to show at least this kind of strong dependence is 0.0019.}

\text{Thus, the probability that they will seem to show at least this kind of strong independence is =}\mathbf{0.0019}

8 0
2 years ago
The length of the hypotenuse is ______
mariarad [96]
A^2+b^2=c^2
10^2+24^2=c^2
100+576=c^2
676=c^2
c=26

The length of the hypotenuse is 26.

I hope this helps!! :)
5 0
3 years ago
Read 2 more answers
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