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Aliun [14]
3 years ago
11

Write an equation of a line with a y-intercept of −3 and an x-intercept of −4.5.

Mathematics
1 answer:
Soloha48 [4]3 years ago
6 0

Answer:

Y=(2/3)x-2

Step-by-step explanation:

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Write 60 as the product of two factors
Ilya [14]
Use a factor<span> tree to express </span>60<span> as a </span>product<span> of prime </span>factors<span>. So the prime factorization of </span>60<span> is 2 × 2 × 3 × 5, which can be written as 2 </span>2<span> × 3 × 5.</span>
5 0
3 years ago
Adam is building a rectangular planter without a top the planter will be 7 feet wide 5 feet wide, 5 feet long, and 9 inches high
Tom [10]
Answer: The surface area of the planter will be 120.5 square feet.

In our shape, we will have 5 sides. The base and the four sides going up from each edge of the base.

The base will be 7 x 5 = 35 square feet.

The front and back side will each be 7 x 0.75 = 5.25 square feet.

The left and right side will each be 5 x 0.75 = 3.75 square feet.

If we add up the 5 faces we get:
35 + 5.25 + 5.25 + 3.75 + 3.75 = 120.5 square feet
8 0
3 years ago
En una pizzeria se hicieron 8 docenas de pizzas. La tercera parte se vendio en el local y las cinco octavas partes son para envi
11111nata11111 [884]

Answer:

32 pizzas

60 pizzas

1/24

Step-by-step explanation:

Se hicieron 8 docenas de pizzas.

Una docena es 12, por lo tanto, el número de pizzas hechas fue:

8 * 12 = 96 pizzas

1/3 se vendieron en el local, esto significa que el número de pizzas vendidas en el local es:

1/3 * 96 = 32 pizzas

5/8 fueron para entrega a domicilio, por lo tanto, el número de pizzas vendidas en casa es:

5/8 * 96 = 60 pizzas

El número total de pizzas vendidas es:

32 + 60 = 92 pizzas

Esto significa que no se vendieron 4 pizzas. En forma de fracción:

4/96 = 1/24

5 0
3 years ago
About 33% of people who get their feet examined are found to have an ingrown toenail. What is the probability of a podiatrist ex
enot [183]

Answer:

The correct answer is 0.94147

Step-by-step explanation:

Let A denote the event that the podiatrist finds the first person with an ingrown toenail.

And (1 - A) denote the event that the podiatrist does not find the ingrown toenail.

While examining seven people, the podiatrist can find the very first person to have an ingrown toenail. Similarly he can find the second patient to have the ingrown toenail. Going in this way the probability of the first person to have an ingrown toenail is given by:

= A + (1 - A) × A + (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) ×  (1 - A) × (1 - A) × (1 - A) × (1 - A) × A.

= \frac{1}{3} + \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} .

= \frac{1}{3} + \frac{2}{3} \frac{1}{3} + (\frac{2}{3}) ^{2} \frac{1}{3} + (\frac{2}{3})^{3} \frac{1}{3} + (\frac{2}{3})^{4} \frac{1}{3} + (\frac{2}{3})^{5} \frac{1}{3} + (\frac{2}{3})^{6} \frac{1}{3}.

= 0.94147

We can also solve the above expression by using the geometric progression formula as well where common ratio is given by \dfrac{2}{3}.

8 0
3 years ago
I need help on this hhhhhhhh​
Anon25 [30]

\huge\text{Hey there!}

\mathsf{\dfrac{10^{15}}{10^4}}

\mathsf{10^{15}}\\\mathsf{=10\times10\times10\times10\times10\times10\times10\times10\times10\times10\times 10\times10\times10\times10\times10}\\\mathsf{= \boxed{\bf 1,000,000,000,000,000}}

\mathsf{\dfrac{\bold{1,000,000,000,000,000}}{10^4}}

\mathsf{10^4}\\\mathsf{= 10\times10\times10\times10}\\\mathsf{10\times10=\bf 100}\\\mathsf{100\times100}\\\mathsf{= \boxed{\bf 10,000}}

\mathsf{\dfrac{1,000,000,000,000,000}{\bf 10,000}}

\mathsf{\dfrac{1,000,000,000,000,000}{10,000}}\\\\\mathsf{= 1,000,000,000,000,000\div 10,000}\\\\\mathsf{= \boxed{\bf 100,000,000,000}}

\mathsf{10^{11}}\\\mathsf{10\times10\times10\times10\times10\times10\times10\times10\times10\times10\times10}\\\mathsf{= \boxed{\bf 100,000,000,000}}

\mathsf{100,000,000,000= 100,000,000,000= 10^{11}}

\boxed{\boxed{\large\text{Answer: BASICALLY }\mathsf{\dfrac{10^1^5}{10^4}\large\text{ is EQUAL to or EQUIVALENT to}}}}\\\boxed{\boxed{\mathsf{10^{11}}\large\text{ because they both give you the result of \bf 100,000,000,000}}}\huge\checkmark

\large\textsf{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

3 0
2 years ago
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