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3 years ago

PLEASE HELP ME AGAIN, I REALLY NEED IT.

Mathematics

2 answers:

Angelina_Jolie [31]3 years ago

5 0

Answer + Step-by-step explanation:

3. {($2 ÷ by the pound) x lbs. of peaches} + ($1.50 x lbs. of apples) = $15

4. {(16mi. ÷ by the hour) x hours biked) + {(2mi. ÷ by the hour) x hours walked} = 32 miles

Aleksandr-060686 [28]3 years ago

4 0

Answer:

$2/p x peaches+$1.5/p x apples=15

16/h x hb+2/h x hw=32

Here you go, hopw this helps! :-)

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A line passes through the point (-8, 4) and has a slope of - 5/4.

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Answer:

Point-slope equation is

y-y1 = m(x-x1)

m is a slope, m=5/4

y1 = -5, x1 = 8

Point-slope equation is

y+5 = 5/4(x - 8).

Step-by-step explanation:

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$x=\frac{3h-32}{4-h};$ $h\neq 4$

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Karen will divide her garden into equal parts. She will plant corn in 8/12 of the garden. What is the lowest number of parts she

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3 years ago

The perimeter of a triangular field is 120m. Two of the sides are 21m and 40m.Calculate the largest angle of the field.

Mama L [17]

Answer:

the largest angle of the field is 149⁰

Step-by-step explanation:

Given;

perimeter of the triangular filed, P = 120 m

length of two known sides, a and b = 21 m and 40 m respectively

The length of the third side is calculated as follows;

a + b + c = P

21 m + 40 m + c = 120 m

61 m + c = 120 m

c = 120 m - 61 m

c = 59 m

↓ ↓

A → → → → → → → → → → → C

Consider ABC as the triangular field;

Angle A is calculated by applying cosine rule;

$a^2 = b^2 + c^2 - 2bc \ Cos A\\\\Cos \ A = \frac{b^2 + c^2 - a^2}{2bc} \\\\Cos \ A = \frac{40^2 + 59^2 - 21^2}{2 \times 40 \times 59} \\\\Cos \ A = 0.983\\\\A = Cos ^{-1} (0.983)\\\\A = 10.6 \ ^0$

Angle B is calculated as follows;

$Cos \ B = \frac{a^2 + c^2 - b^2}{2ac} \\\\Cos \ B = \frac{21^2 + 59^2 - 40^2}{2 \times 21 \times 59} \\\\Cos \ B = 0.937\\\\B= Cos ^{-1} (0.937)\\\\B = 20.5 \ ^0$

Angle C is calculated as follows;

$Cos \ C = \frac{a^2 + b^2 - c^2}{2ab} \\\\Cos \ C = \frac{21^2 + 40^2 - 59^2}{2 \times 21 \times 40} \\\\Cos \ C = -0.857\\\\C = Cos ^{-1} (-0.857)\\\\C = 149\ ^0$

Therefore, the largest angle of the field is 149⁰.

8 0

3 years ago