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stellarik [79]
3 years ago
7

If a kennel has 50 dogs and some of them are puppies and some of them are adult dogs . The ratio of puppies to adult dogs in a k

ennel are 2:3 . How many puppies are there?
Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
5 0

The ratio is 2:3 puppies to adult dogs, which means for every 2 puppies, there is 3 adult dogs.


Add the ratio together: 2+3 = 5

Divide total dogs by that total: 50 dogs / 5 = 10

Now multiply each number of the ratio by that to find the total number of each:

2 puppies x 10 = 20 total puppies.

3 adults x 10 = 30 total adult dogs.

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Evaluate the function f\left(x\right)=5x+2\mid11-5x\mid-4f(x)=5x+2∣11−5x∣−4 for x = -5.
Anestetic [448]

Answer:

f\left(5\right) = 43

Step-by-step explanation:

Given

f\left(x\right)=5x+2\mid11-5x\mid-4

Required

Solve for x = -5

This implies that we substitute -5 for x in f\left(x\right)=5x+2\mid11-5x\mid-4

f\left(5\right)=5(-5)+2\mid11-5(-5)\mid-4

Open all brackets

f\left(5\right) = -25+2\mid11+25\mid-4

f\left(5\right) = -25+2\mid36\mid-4

Absolute value of 36 is 36; Wo, we have:

f\left(5\right) = -25+2*36-4

f\left(5\right) = -25+72-4

f\left(5\right) = 43

7 0
3 years ago
Pam made 1/2 gallon of tea for 10 people. Each person gets the same amount of tea. How much tea, in gallons, will each person ge
OverLord2011 [107]
You just divided 1/2 (.5) by 10 which is .05. so the answer is 0.05 gallons
6 0
3 years ago
Distance = 30 m, Time = 6 minutes, Speed = ?<br><br><br> Helpppp
Yanka [14]

Answer:

its 5 m/minute

Step-by-step explanation:

you have to use the units that are given in the equation

pls mark brainliest if you geel like it...

7 0
3 years ago
Read 2 more answers
I think I got it! It's a math problem and I hope you can see and solve this! If you can't, I tried.
denis-greek [22]
I don’t get it but probably the scissors lol
6 0
3 years ago
A data set of 27 different numbers has a mean of 33 and a median of 33. A new data set is
Svetllana [295]

Answer:

Option D.

Step-by-step explanation:

Suppose that we have a set of N values:

{x₁, x₂, ..., xₙ}

The median is the value in the middle, and the mean is calculated as:

M = \frac{(x_1 + x_2 + x_3 ... + x_n)}{N}

Because here we have "the median" then we will assume that N is odd, and there is only one median, the value "k"  (if N was even, the median would be the mean of the two middle values, that case is really similar to the case where N is odd, so solving only one of the cases is enough)

Now we add 7 to all the values greater than the median

We subtract 7 to all values smaller than the median.

Then the median remains unchanged (because we did not add nor subtract anything to the median).

The new mean will be:

M' = \frac{(x_1 - 7) + (x_2 - 7) + ... + (x_{k}) + ... + (x_n + 7)}{N} = \frac{(x_1 + x_2 + ... + x_n) + (-7)*(n/2 - 0.5) + 7*(n/2 - 0.5)}{N}  = \frac{(x_1 + x_2 + ... + x_n)}{N} = M

So the mean does not change.

Because the mean is computed as the sum of the numbers divided by N, and the mean does not change, and N does not change, then the sum of the numbers does not change.

Finally, the standard deviation is computed as:

SD = \sqrt{\frac{(x_1 - M)^2 + ... + (xn - M)^2}{N} }

Because M does not change, if we add or subtract numbers to some of the values, the standard deviation will change (Because all the terms are squared, so the added and subtracted sevens don't cancel like in the previous cases)

Then the only value that does not have the same value in both the original and new data sets is the standard deviation.

6 0
3 years ago
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