Answer:
First question, x= 10^10.
Second question is 10!. or 362880
Step-by-step explanation:
First Question:
Simple logx has a base of 10, i.e log10 x,
the question will be 10 = log10 x,
when taking the base "10" from the right side to the left, the number on the left side becomes the power of the base, in this case 10 from the right will be base and 10 from the left will power and log will vanish.
x=10^10.
Another example with different numbers
Y=logx if Y= 12, What is x?
The base is ten when not given,so:
12=logx
10^12=x
Second Question;
simple multiplication just multiply the numbers.
10! is pronounced as 10 factorial,
5! will be 5x4x3x2x1=120
To make a box and whisker plot, first you write down all of the numbers from least to greatest.
0, 1, 3, 4, 7, 8, 10
The median is 4, so that’s the middle line of the plot.
So now we have:
0, 1, 3, [4,] 7, 8, 10
So next we have to find the 1st and 3rd interquartiles..
0, [1,] 3, [4,] 7, [8,] 10
Those are the next 2 points you put on the plot.
Lastly, the upper and lower extremes. These are the highest and lowest numbers in the data.
[0,] 1, 3, 4, 7, 8, [10]
These are the final points on the plot.
To make the box of a box-and-whisker plot, you plot the 3 Medians of the data: 1, 4, and 8, and connect those to make a box that has a line in the middle at 4.
Next, you plot the upper and lower extremes: 0 and 10, by making “whiskers” that connect to the box. So you draw a line from the extremes to the box.
Answer: B. 10
-5C3 or 5 choose 3 refers to how many combinations are possible from 5 items, taken 3 at a time. To calculate combinations, we will use the formula nCr = n! / r! ... * (n - r)!, where n represents the total number of items, and r represents the number of items being chosen at a time.
-10 is the total number of all possible combinations for choosing 3 elements at a time from 5 distinct elements without considering the order of elements in statistics & probability surveys or experiments. The number of combinations for sample space 5 CHOOSE 3 can also be written as 5C3 in the format of nCr or nCk.
Step-by-step explanation: Hope this help :D
