Answer:
import java.util.Scanner;
public class num2 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int total = 0;
for(int i=0; i<5; i++){
System.out.println("Enter next Int: ");
total = total+in.nextInt();
}
System.out.println(total);
}
}
Explanation:
In the code above written in Java programming language, the for loop statement for(int i=0; i<5; i++) ensures that the loop goes from 0-4 a total of five times.
At each iteration it requests a user to enter an int. The number entered is stored in the variable total which is initially assigned 0.
When the loop finishes execution, total is printed out
When computers need to use more memory than have RAM, they'll swap out pages of memory to their drive. When they need those memory pages, they'll swap out others and swap in the needed ones. If a computer needs enough additionall memory, it can get so busy swapping that it doesn't have any (or very little) time to do any useful work. That is called thrashing.
Unix calls swapping swapping. Windows calls it paging, probably because of the memory pages. Memory pages are 4096 (4KB) sections of memory.
Unix drives are usually partitioned with a swap partition, and swap files can be made in the filesystem. Windows just has pagefiles[s].
If an administrator needs to renew a certificate for a web server he/she should submit the CSR (Certificate Signing Request) to CA.
<span>If a security administrator is required to submit a new CSR to a CA, teh fisrt step the administrator should do is to g</span>enerate a new private key based on RSA.
That is true. I hope this helps
