10.......................................
Answer:
see explaination
Explanation:
import java.io.*;
import java.util.Scanner;
public class Winners {
public static void main(String args[]) throws IOException {
Scanner sc = new Scanner(new File("WorldSeriesWinners.txt"));
String commands[] = new String[100000];
int c = 0;
while (sc.hasNextLine()) {
String input = sc.nextLine();
System.out.println(input);
if (input.isEmpty())
continue;
commands[c++] = input;
}
sc.close();
Scanner keyboard = new Scanner(System.in);
System.out.println("Enter the name of a team: ");
String name = keyboard.nextLine();
int count = 0;
for (int i = 0; i < c; i++) {
if (commands[i] != null) {
if (commands[i].equals(name)) {
++count;
}
}
}
if(count!=0)
System.out.println(name + " has won the World Series in the time period from 1903 through 2018 " +count + " number of times" );
else
System.out.println("Team with name "+name+ " does not exists");
}
}
Answer:
Chunking
Explanation:
Chunking refers to the process of taking individual pieces of information (called chunks) and grouping them into larger units. By grouping each piece into a large whole, you can improve the amount of information you can remember.
Answer:
Option (B) is the correct answer to the following question.
Explanation:
Here, in the code "const" is the constant keyword which is used when we need that the value stored in that variable will never change.
The following option is correct because the assignment operator are those operator which initialize the value in the variable and overloading of the assignment operator would be as we use the other operators and also we could use them by creating the objects as we use in the copy constructor.
So, that's why the following option is correct.
