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vovikov84 [41]
3 years ago
5

Which series of transformations will always carry an image onto the original figure? reflection over the y-axis followed by refl

ection over the x-axis
rotation by 180° about the origin
reflection over the x-axis followed by reflection over the y-axis
rotation by 360° about the origin
Mathematics
2 answers:
krek1111 [17]3 years ago
8 0
The answer to your question is reflection of the y axis followed by a reflection over the x axis.
let me know if you have any other questions
:)
irinina [24]3 years ago
5 0

Answer:

reflection of the y axis followed by a reflection over the x axis.

Step-by-step explanation:

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Mr. Loretta spends $4.83 on pens and notebooks. Pens cos $0.95 each. Notebooks cost $0.99 each. How many of each item does he bu
VMariaS [17]
<h2>The total number of items does he buy 5 (three pens and two notebooks).</h2>

Step-by-step explanation:

The total amount spend by Mr. Loretta = $4.83

The cost of each pen = $0.95 and

The cost of each notebook = $0.99 and

To find, total number of items he buy = ?

∴ The cost of one pen and one notebook = $0.95 + $0.99 = $1.94

The cost of two pens and two notebooks = $1.94 × 2 = $3.88

∴ The cost of three pens and two notebooks  = $3.88 + $0.95 = $4.83

Thus, the total number of items does he buy 5 (three pens and two notebooks).

4 0
3 years ago
Jon has 6 kites he and his friends will each fly one kite how many people in all will fly a kit
True [87]

Answer:

  6

Step-by-step explanation:

One person will fly a kite for each of the 6 kites Jon has.

6 people in all will fly a kite.

6 0
3 years ago
The amount of warpage in a type of wafer used in the manufacture of integrated circuits has mean 1.3 mm and standard deviation 0
valina [46]

Answer:

a) P(\bar X >1.305)=P(Z>\frac{1.305-1.3}{\frac{0.1}{\sqrt{200}}}=0.707)

And using the complement rule, a calculator, excel or the normal standard table we have that:

P(Z>0.707)=1-P(Z

b) z=-0.674

And if we solve for a we got

a=1.3 -0.674* \frac{0.1}{\sqrt{200}}=

So the value of height that separates the bottom 95% of data from the top 5% is 1.295.

c) P( \bar X >1.305) = 0.05  

We can use the z score formula:

P( \bar X >1.305) = 1-P(\bar X

Then we have this:

P(z< \frac{1.305-1.3}{\frac{0.1}{\sqrt{n}}}) = 0.95

And a value that accumulates 0.95 of the area on the normal distribution z = 1.64 and we can solve for n like this:

n = (1.64*\frac{0.1}{1.305-1.3})^2= 1075.84 \approx 1076

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Part a

Let X the random variable that represent the amount of warpage of a population and we know

Where \mu=1.3 and \sigma=0.1

Since the sample size is large enough we can use the central limit theorem andwe know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

We can find the probability required like this:

P(\bar X >1.305)=P(Z>\frac{1.305-1.3}{\frac{0.1}{\sqrt{200}}}=0.707)

And using the complement rule, a calculator, excel or the normal standard table we have that:

P(Z>0.707)=1-P(Z

Part b

For this part we want to find a value a, such that we satisfy this condition:

P(\bar X>a)=0.75   (a)

P(\bar X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.25 of the area on the left and 0.75 of the area on the right it's z=-0.674. On this case P(Z<-0.674)=0.25 and P(z>-0.674)=0.75

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-0.674

And if we solve for a we got

a=1.3 -0.674* \frac{0.1}{\sqrt{200}}=

So the value of height that separates the bottom 95% of data from the top 5% is 1.295.

Part c

For this case we want this condition:

P( \bar X >1.305) = 0.05  

We can use the z score formula:

P( \bar X >1.305) = 1-P(\bar X

Then we have this:

P(z< \frac{1.305-1.3}{\frac{0.1}{\sqrt{n}}}) = 0.95

And a value that accumulates 0.95 of the area on the normal distribution z = 1.64 and we can solve for n like this:

n = (1.64*\frac{0.1}{1.305-1.3})^2= 1075.84 \approx 1076

6 0
3 years ago
SI AL CUADRADO DE LA EDAD DE ROSA LE DISMINUYES EL TRIPLE DE SU EDAD OBTIENES UN VALOR IGUAL A 108 . DETERMINA LA EDAD DE ROSA
FromTheMoon [43]
Okay thank goodness for you guys going home
7 0
2 years ago
Joe is building a container to hold sand for a beach party. The container will hold 9,000 cubic feet of sand. Of the base of the
Genrish500 [490]

Answer:

The height of the container is 4 feet.

Step-by-step explanation:

A container has the format of a rectangular prism.

It has three dimensions: width(w), length(l), height(h).

The volume is:

V = w*l*h

In this question:

w = 45, l = 50, V = 9000

We have to find the height(length and width are in feet, volume in cubic feet, so the height will be in feet).

V = w*l*h

9000 = 45*50*h

h = \frac{9000}{45*50}

h = 4

The height of the container is 4 feet.

7 0
3 years ago
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