All categories

3 years ago

HELP ASAP!!!!!!!!!!!!!!!!!!What is the distance between the points (–3, 4) and (–7, 4)?

2 answers:

7 0

By the Pythagorean Theorem:

c^2=a^2+b^2

And then some refer to this as the distance formula...

d^2=x^2+y^2

And when you are dealing with two points...

d^2=(dx)^2+(dy)^2

In this case:

d^2=(-7--3)+(4-4)^2

d^2=(-4)^2+0^2

d^2=16

d=4

So the distance between the two point is 4 units.

(We could have just noticed that the y coordinates were the same and said the distance was just -3--7=4 :P, but the way I worked it is how you will almost always have to.)

sasho [114]3 years ago

5 0

HELP ASAP!!!!!!!!!!!!!!!!!!What is the distance between the points (–3, 4) and (–7, 4)?

A.
0

You might be interested in

Find the value of x. A.20 B.25 C.18.75 D.22.5

miss Akunina [59]

The two equations are vertical angle, which would be equal to each other.

Set the equations to equal and solve for x:

5x -10 = 3x +40

Subtract 3x from both sides:

2x -10 = 40

Add 10 to both sides:

2x = 50

Divide both sides by 2:

x = 50 / 2

x = 25

The answer is B. 25

7 0

3 years ago

Read 2 more answers

HELP!!!!!!!!!!!!!!! please show your work, look at the picture

Margarita [4]

Answer:

B= 2y(3)/7x(8)

C= 12/ x(3) y(3)

D= The same because nothing else can be done with it

(parnthaces) are exponents

6 0

2 years ago

Solve the proportion 2x+1/6 = 7/9

Paul [167]

Answer: x=11/36

Step-by-step explanation:

Step One-Subtract 1/6 from both sides.

2x+1/6-1/6=7/9-1/6

2x=11/18

Step Two-Divide both sides by 2.

2x/2=11/18/2

x=11/36.

My math might not be correct, sorry if it is. In addition, my explanation is a bit confusing, so sorry about that too.

8 0

2 years ago

2 log x + log 11 WILL MARK BRAINLIEST

tester [92]

Answer:

$log(11 {x}^{2} )$

Step-by-step explanation:

$2logx + log11 \\ \\ = log {x}^{2} + log11 \\ \\ = log( {x}^{2} \times 11) \\ \\ = log(11 {x}^{2} )$

3 0

3 years ago

Please Help!

Flura [38]

Let x be the length of the train.

On the basis of the observer;
Speed of the train = x/6

On the basis of the bridge;
Total distance covered by any point of the train= 350+x
Speed = (350+x)/20

Equating the two expressions of speed;
x/6 = (350+x)/20
20(x) = 6(350+x)
20x = 2100+6x
(20-6)x = 2100
14x = 2100
x= 2100/14 = 150 m
Speed = x/6 = (350+x)/20 = 150/6 = 500/20 = 25 m/s.

Therefore,
Length of train = 150 m
Speed of train = 25 m/s

8 0

3 years ago