JAVA programming was employed...
What we have so far:
* Two 2x3 (2 rows and 3 columns) arrays. x1[i][j] (first 2x3 array) and x2[i][j] (second 2x3 array) .
* Let i = row and j = coulumn.
* A boolean vaiable, x1rules
Solution:
for(int i=0; i<2; i++)
{
for(int j=0; j<3; j++)
{
x1[i][j] = num.nextInt();
}
}// End of Array 1, x1.
for(int i=0; i<2; i++)
{
for(int j=0; j<3; j++)
{
x2[i][j] = num.nextInt();
}
}//End of Array 2, x2
This should check if all the elements in x1 is greater than x2:
x1rules = false;
if(x1[0][0]>x2[0][0] && x1[0][1]>x2[0][1] && x1[0][2]>x2[0][2] && x1[1][0]>x2[1][0] && x1[1][1]>x2[1][1] && x1[1][2]>x2[1][2])
{
x1rules = true;
system.out.print(x1rules);
}
else
{
system.out.print(x1rules);
}//Conditional Statement
The command is more.
hope this helps.
Answer: netstat -a
Explanation: The netstat -a command displays both listening and non-listening sockets.
The answer is Database assuming those are the answer choices
Answer: B) conducting requirements structuring.
Explanation:
The Key physical database design decisions usually include: deciding on the storage format as well as physical storage that makes access to database more efficient, design practices which aid quick retrieval, and attributes grouping into physical records. So the following are key design decisions but conducting requirements structuring is not.
A) choosing the storage format for each attribute from the logical database model.
C) arranging related records in secondary memory so that individual and groups of records can be stored, retrieved, and updated rapidly.
D) selecting media and structures for storing data to make access more efficient.
E) grouping attributes from the logical database model into physical records
